There are 5 distinct integers a, b, c, d, e in ascending order.

(68-a)(68-b)(68-c)(68-d)(68-e) = 725.
What is a + b + c + d?

• Factors of 725 = 29 * 5 * 1 * (-1) * (- 5)
  consider abcde in Ascending Order so
  a = 39
  b = 63
  c = 67
  d = 69
  a+b+c+d = 238
• 9 years agoHelpfull: Yes(3) No(1)
• Prime factorisation of 725 =29*5*5*1*1
  therefore a=39; b=63; c=63; d=67; e=67
  a+b+c+d=232
• 9 years agoHelpfull: Yes(1) No(2)
• 725 = 29* 5*1* (-1)*(-5)
  a= 39 b= 63 c= 67 d=69 e= 73
  a+b+c+d+e = 311
• 9 years agoHelpfull: Yes(1) No(1)
• a=39
  b=63
  c=67
  d=69
  e=73
  a+b+c+d=238
  
• 9 years agoHelpfull: Yes(0) No(0)
• Find LCM of 725 first. we have, 725=5x5x29x1x1
  For 5 digits to be multiplied, we subtract a number to obtain each corresopndinfg multiple.
  68-63=5
  68-39=29
  68-67=1
  hence, a=63,b=63,c=39,d=67,e=67...
  you can let any value from this 5 numbers. sum up the values and check for the correct option
• 9 years agoHelpfull: Yes(0) No(0)
• a=39; b=63; c=67; d=69; e=73
  a+b+c+d=238
• 9 years agoHelpfull: Yes(0) No(0)
• Y taking -1 and -5 and not positive of these numbers??
• 9 years agoHelpfull: Yes(0) No(0)