In the elitmus forum it's been found that out of all student 50% of student write in the forum out which 36% student write about 3 companies I.E. midntree, tintel , kosch and it's been found that the number of student that wrote about midntree is double of the number of student that write about tintel , which in turn is double of the number of students that write about kosch. And it's been known that number of student that wrote about kosch is 7560 than is the number of student present in the blog :
1- 126000
2- 156000
3- 168000
4- Can't be determined

• no of students that write about
  kosch: 7560
  tintel: 2*7560
  midntree: 4*7560
  they are among 36% of 50% of total students
  so,
  (36/100)*(50/100)*X=7560*7
  X=294000
• 8 years agoHelpfull: Yes(24) No(3)
• Given
  K=7560.
  T=2K=15120
  M=2T=30240
  TOTAL=M+T=K=52920
  
  They are the 36 % of present student
  => 36/100*x=52920
  => x=52920*100/36
  => x=147000
  not in options
• 8 years agoHelpfull: Yes(3) No(2)
• Students in forum those are writting about IE,Mind, Tint, Kos is = 36/100[(50/100)*s]
  Let no of student writting about tint=x=kos n mind=2x
  Where x=7560 is given
  Then
  4*5760=36/100[(50/100)*s]
  S= 168000
• 8 years agoHelpfull: Yes(3) No(7)
• x*50%*36%=7560+15120+30240
  x=73500
  
• 8 years agoHelpfull: Yes(2) No(1)