Elitmus Exam Numerical Ability Log and Antilog

f(x)=logaX+logbXwhere1

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the full question is not getting printed
8 years agoHelpfull: Yes(0) No(0)

please post full question
8 years agoHelpfull: Yes(0) No(0)
f(x)=logX/loga+logX/logb
f(x)=logX(1/loga+1/logb)
X=1
log1=0
so F(x)=0 ans
8 years agoHelpfull: Yes(0) No(1)

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4- Can't be determined Q)f(x)=log(base a)x + log(base b)x where 1