4 years before Paul’s age is 3times the Alice age and the present age of Paul is 6times
the Alice. What is the presents Paul’s age?

• Not possible .
  As acc. to question let paul's age=p and that of alice is a.
  p-4=3(a-4)
  p=6a
  6a-4=3a-12
  3a=-8 which is not possible.
• 8 years agoHelpfull: Yes(3) No(1)
• Not possible .
  let paul's age=p and that of alice is a.
  p-4=3(a-4)
  p=6a
  6a-4=3a-12
  3a=-8 which is not possible.
• 8 years agoHelpfull: Yes(2) No(0)
• 16 z pauls age
• 8 years agoHelpfull: Yes(1) No(0)
• 16 is answer,
  let p,a are present ages of paul and alice,
  4 years before
  p-4=3(a-4)
  present ages
  p=6a,
  substitute a=(p/6) in first equation
  
• 8 years agoHelpfull: Yes(1) No(0)
• p-4=3a
  p=6a
  6a-4=3a
  3a=4
  
  putting in above eaquation
  p=3a+4
  =4+4=8
  answer is 8
• 8 years agoHelpfull: Yes(0) No(0)
• 4 years ago
  alice age=x
  paul's age=3x
  present situation
  alice age=y+4
  paul's age=6(x+4)-----i
  also pauls age=3x+4------ii
  equating 1 and ii,we get
  6(x+4)=3x+4
  6x+24=3x+4
  3x=-20
  x= -20/3 which is not possible
  therefore ...answer is not possible
• 8 years agoHelpfull: Yes(0) No(0)