What is the unit place of the sum
(12)^41+(66)^66+(25)^15+(51)^61+4321



a)1
b)3
c)8
d)6

• anser is 5 all options are wrong
  
• 8 years agoHelpfull: Yes(9) No(0)
• 2+6+5+1+1=15
  so unit place will be 5
• 8 years agoHelpfull: Yes(7) No(0)
• 12^41=last digit=2
  66^66= last digit=6
  25^15= last digit=5
  51^61= last digit=1
  4321 = last digit=1
  so last digit=2+6+5+1+1=15
  so last digit=5
  
• 8 years agoHelpfull: Yes(5) No(0)
• I think the answer is 6
• 8 years agoHelpfull: Yes(3) No(5)
• plz explain the and...
  
• 8 years agoHelpfull: Yes(1) No(0)
• ans will be 6
  take first term 12^41,concentrate on 2 (unit digit) and 41
  the cycle of 2 is 4 (2,4,8,16,32)
  so divide 41 by 4 ,remainder is 1 so unit digit of 12^41=2^1=2
  similarly cycle of 6 is 1 ,remainder is 0 so unit digit of 66^66=6^0=1
  same for 25^15 unit digit=1
  51^61=1
  so adding 2+1+1+1+1=6
• 8 years agoHelpfull: Yes(1) No(10)
• Answer is 5.......
• 8 years agoHelpfull: Yes(1) No(1)
• Ans; 5
  
  
  
  
  
  
  
• 8 years agoHelpfull: Yes(1) No(0)
• The answer is 3 (b)
• 8 years agoHelpfull: Yes(0) No(2)
• how? answer is 3,@@@@@@KROVVIDI ANANTH DUTT
  can you please explain me.
• 8 years agoHelpfull: Yes(0) No(0)
• Ans is 3(b)
• 8 years agoHelpfull: Yes(0) No(0)
• Answer will be 5
• 8 years agoHelpfull: Yes(0) No(0)
• It's a dummy question. Answer is 5.
• 8 years agoHelpfull: Yes(0) No(0)