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what is the reminder when 6^17 +17^6 is devide by 7 ???
i) 1
ii)6
iii)3
iv) 0
Read Solution (Total 5)
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- 6^17 mod 7=(7-1)^17 mod 7=(-1)^17 mod 7=-1
17^6 mod 7=(7*2+3)^6 mod 7= (3)^6 mod 7=729 mod 7=1
the remainder when 6^17+17^6 is divided by 7 is
1-1=0(ans)
Read more at http://www.m4maths.com/10628-What-is-the-remainder-when-6-17-17-6-is-divided-by-7-a-1-b-6-c-0-d.html#41g3aLjzPGye6U6y.99 - 9 years agoHelpfull: Yes(6) No(0)
- ans is 0 (36*36*36*36)^2*6+(17*17*17)^2/7
then remainder for dividing each 36 with 7 and 17 with 7 is:
((1*1*1*1)^2*6+(3*3*3)^2)/7
6+1=7/7=0 so, ans is 0 - 9 years agoHelpfull: Yes(3) No(0)
- Correct answer is C
- 9 years agoHelpfull: Yes(2) No(2)
- 6/7 reminder 6. 6*17=102. 102/7 reminder 4.
17/7 reminder 3. 3*6=18. 18/7 reminder 4.
4+4=8. hence it is greater than 7 then 8/7 reminder 1.
1 is the answer - 9 years agoHelpfull: Yes(0) No(1)
- Ans: iv) 0 (Zero)
- 9 years agoHelpfull: Yes(0) No(1)
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