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jake and paul start together to walk 10 kms.jake walks 1.5 KMPH faster than paul and arrives at his destination 1.5hrs earlier than paul.jakes’s speed of walking is:
Read Solution (Total 4)
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- paul speed x and jake speed x+1.5
time=distance/speed
10/x-10/(1.5+x)=1.5
x=2.5
ans is : 2.5+1.5=4 KMPH
- 8 years agoHelpfull: Yes(17) No(0)
- this is quit simple problem.
- 8 years agoHelpfull: Yes(2) No(2)
- Jake's speed = J
Paul's speed = P
Therefore, J = 1.5P
Now,
(10/P) - (10/1.5P) = 1.5
Solving , P = 1.15KMPH
Therefore Jake's speed = (1.15*1.5) = 1.725KMPH
Answer = Jake's speed = 1.725KMPH
- 8 years agoHelpfull: Yes(0) No(16)
- paul speed x and jake speed x+1.5
time=distance/speed
10/x-10/(1.5+x)=1.5
x=2.5
ans is : 2.5+1.5=4 KMPH - 7 years agoHelpfull: Yes(0) No(1)
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