Find the probability that a leap year chosen at random will have 53 sunday.

• Answer is 2/7 as 365=52*7+2 , 2 days can be any of sun mon ,mon tue ,tue wed, wed thur ,thur fri ,fri sat, sat sun. in two of the cases there is sunday so probability is 2/7
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• The possibility is (sun mon),(mon tues),(tues wed)(wed thus),(thus frid)(frid sat),(sat sun) this give seven pair we have only two sunday so the answer of the question is 2/7;
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• 52 weeks+2 days and these 2 days can be mon tue wed thurs fri sat sun ..so 2/7
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• there are 52 weeks +2 days,hence ans =2/7
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• 2/7
  52 weeks*7 days=364 days
  now 2 days left
  either it can be sunday-monday or sat-sunday out of 7 days
  so 2/7
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