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consider the sequence 1,-2,3,-4,5,-6......what is the Average of the first 200 terms of the sequence?
Read Solution (Total 6)
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- (1-2)=-1
(3-4)=-1.....similarly (199-200)=-1
so total 100 set.
(-1)100/200 =-0.5
ans=-0.5
- 8 years agoHelpfull: Yes(5) No(0)
- 1+3+5.....n=n^2 {here n=100} , -(2+4+6.....)=-[n(n+1)] {here n=100 }
total sum=n^2-n(n+1)=-n
average= sum/no.of terms
= -n/200
=-100/200
=-0.5 - 8 years agoHelpfull: Yes(2) No(0)
- 7
odd positions--> 1 3 5 and hence 7 - 8 years agoHelpfull: Yes(0) No(0)
- no. of terms =200 means 100 odd and 100 negative even
sum of 1+3+5.........n = n^2 and sum of -(2+4+6......n) = -[n(n+1)]
total sum = n^2-n(n+1) = 100^2-[100(100+1)] = 10000-10100 = -100
average=Total sum/no. of total terms
= -100 / 200
=-0.5 - 8 years agoHelpfull: Yes(0) No(0)
- -100/200=-.5
- 8 years agoHelpfull: Yes(0) No(0)
- -100/200=-.5
- 8 years agoHelpfull: Yes(0) No(0)
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