Rajiv can do a piece of work in 10 days , Venky in 12 days and Ravi in 15 days. They all start the work together, but Rajiv leaves after 2 days and Venky leaves 3 days before the work is completed. In how many days is the work completed ?

• (t/15)+(2/10)+((t-3)/12)=1
  or, t=7 days.....Enjoy guys
• 9 years agoHelpfull: Yes(28) No(1)
• (Rajiv +venky+ravi) 2 days work= 2(1/10+1/12+1/15)=1/2
  ravi works alone for last 3 days = 3*1/15=1/5
  total work 1/2+1/5=7/10
  remaining work=1-7/10=3/10
  (venky+ravi) 1 days work=1/12+1/15=9/60=3/20
  3/10 work will be done by venky and ravi in 3/10*20/3=2 days
  total days is the work completed= 2+3+2=7 days
• 9 years agoHelpfull: Yes(21) No(1)
• Take total work as 60 ; efficiency of rajiv is 60/10 =6;effic of venky = 5; of ravi = 4;
  for 2 days all work together so 15*2 = 30 ; remaining=30;
  for last 3 days ravi works alone so 3*4=12 ; remaining 18 units work completed by venky and ravi in 18/9=2 days , total no of days = 2+3+2=7
  
• 9 years agoHelpfull: Yes(11) No(2)
• (Rajiv +venky+ravi)'s 1 days work=(1/10+1/12+1/15)=15/60=1/4
  work done by (Rajiv +venky+ravi) in 2 days=1/4*2=1/2
  work done by ravi in 3 days=1/15*3=1/5
  remaining work=1-(1/2+1/5)=3/10
  work done by (venky+ravi) in 1 day=(1/12+1/15)=3/20
  now,3/10 work is done by (venky+ravi)=20/3*3/10=2
  total days to complete the work is= 2+3+2=7 days
  
• 9 years agoHelpfull: Yes(5) No(0)
• Rajiv : 10 days, Venky : 12 days, Ravi : 15 days
  
  Let total units of work be 60 units (LCM of 10,12,15)
  
  Therefore, Rajiv : 6units/day, Venky : 5units/day, Ravi : 4units/day
  First 2 days : amount of work done = 2*(6+5+4) = 30 // Then Rajiv leaves
  next x days : " = x*(5+4) = 9x // x is the number of days Venky and Ravi works
  last 3 days : " = 3*4 = 12 // Ravi works for the last 3 days
  
  30 + 9x + 12 = 60
  => x = 2
  Therefore, total no. of days = 2 + 2(x) + 3= 7
• 9 years agoHelpfull: Yes(3) No(0)
• 2(1/10+1/12+1/15)+x(1/12+1/15)+3(1/15)=1
  x=2
  Ans=2+2+3=7
• 9 years agoHelpfull: Yes(1) No(1)
• Let the work be 60 units.
  If venky worked for 3 days, and the remaining days of work be x days, total days to complete the work be x + 3 days.
  Now Capacities of Rajiv is 60/10 = 6, Venky is 5, Ravi is 4.
  (6 + 5 + 4) 2 + (5 + 4) (x - 3) + 5 x 3 = 60.
  Solving we get x = 4.
  So total days to complete the work is 7 days.
• 9 years agoHelpfull: Yes(0) No(0)
• to solve T/15+2/10+(T-3)/12 get T=7days
• 9 years agoHelpfull: Yes(0) No(0)
• 5 more days required
• 9 years agoHelpfull: Yes(0) No(0)
• let us consider total work be 120 (L C M of 10,12,15)
  Rajiv 120/10=12works/day
  venky 120/12=10works/day
  ravi 120/15=8works/day
  if they work to gether then complete 30 works per day
  they together work for 2 days means 60 work is completed
  ravi only work for 3 days then 3*8 =24 and 60+24 84 work is completed
  remaining 36 work can be done by venky and ravi in 2 days(36/(10+8))
  so overall 2days+3 days+2 days=7 days
• 9 years agoHelpfull: Yes(0) No(0)