27. Two vehicles A and B leave from city Y to city X. A overtakes B at 10:30am and reaches city X at 12:00pm. It waits for 2 hrs and returns to city Y. on its way it meet B at 3:00pm and reaches city Y at 5:00pm. B reaches city X, waits for 1 hr and returns to city Y. After how many hours will B reach city Y from the time A overtook him for the first time?
o 49.5 hrs
o 37.5 hrs
o 41.5 hrs
o 50 hrs

• Vehicle A overtaken B at 10.30 am and reached X at 12 pm. It started at 2 pm and met B at 3 pm at Q. It means, Vehicle A took one hour to cover distance 'n', So it should be at Q at 11 pm. It is clear that Vehicle A takes 0.5 hour to cover distance 'm'. Now vehicle B travelled from 10.30 am to 3 pm to meet A. So it took 4.5 hours to cover m. So Speeds ratio = 4.5 : 0.5 = 9 : 1.
  Now Vehicle A took a total of 1.5 + 3 = 4.5 hours to travel fro P to Y. So It must take 4.5 × 9 + 1 = 41.5 hours
  
• 9 years agoHelpfull: Yes(19) No(5)
• A vehicle return at 2:00pm and meet with B at 3:00pm means trevel 1 hr.
  answer=41.5hrs
• 9 years agoHelpfull: Yes(0) No(8)