Elitmus
Exam
Numerical Ability
Arithmetic
w^2+x^2)x(y^2+z^2) is always divisible by which of the max no. Where w;x;y;z are odd integers?
Option 20;8;4;2
Read Solution (Total 9)
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- Ans : 4
((odd)^2+(odd)^2)*((odd)^2+(odd)^2)
(even)*(even)
2*2
4 - 9 years agoHelpfull: Yes(9) No(2)
- 4
because if we add two odd number then we gets even number & when we devide that even number can only divisible by 2
so 2*2=4
- 9 years agoHelpfull: Yes(5) No(1)
- In question it is also given that w,x,y,z all are distinct odd numbers, i think this will effect the answer..what to say guys .
- 9 years agoHelpfull: Yes(4) No(2)
- As it is asking max no. so ans should be 20 use hit and trial method
- 9 years agoHelpfull: Yes(2) No(1)
- @ankit
Use hit n trail method and put different odd values... U will find that it is divisible by 4
- 9 years agoHelpfull: Yes(1) No(0)
- According to hit and trail... (49+81) *(25+121) which is 18980 which gives 20 as ans...
- 9 years agoHelpfull: Yes(1) No(0)
- As w,x,y,z are odd so lets take w=9, x=11,y=13,z=15
so 596 is divided by 4 but nither by 20 nor by 8.so answer is 4 - 9 years agoHelpfull: Yes(1) No(0)
- ans- min odd no. is 1 . so ans is 4.
- 9 years agoHelpfull: Yes(0) No(0)
- Maximum no is 20,and it is divided all even no, so ans is 20.
- 9 years agoHelpfull: Yes(0) No(1)
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