find the sum of series 2/5+2/5^2+2/5^3+2/5^4-------------infinite?

• 2/5+2/5^2+2/5^3+2/5^4-------------infinite
  = 2*(1/5+1/5^2+1/5^3+1/5^4-------------infinite)
  
  GP infinite sum = a/(1-r)
  = 2 *(1/5) / (1- 1/5)
  = 1/2
• 9 years agoHelpfull: Yes(44) No(8)
• this is an infinite gp series so the summation will be:
  
  sum= a/(1-r)
  =(2/5)/(1-(3/5))
  =(2/5)/(3/5)
  =2/3
• 9 years agoHelpfull: Yes(9) No(5)
• given gp series is: 2/5+2/5^2+2/5^3+2/5^4..........
  here, r=(2/5^2)/(2/5)= 1/5 , (coz r=2nd term divided by 1st term)
  now, Sum of gp(infinite)= a/(1-r)
  => (2/5)/(1-1/5)
  =1/2
• 9 years agoHelpfull: Yes(4) No(1)
• this is an infinite gp series so the summation will be:
  
  sum= a/(1-r)
  =(2/5)/(1-(3/5))
  =(2/5)/(3/5)
  =2/3
• 9 years agoHelpfull: Yes(3) No(4)
• Sum=a/(a-r)
  Sum=2/5/(1-2/5)=2/3
• 9 years agoHelpfull: Yes(1) No(1)
• @rakesh:
  its not written properly whether it is 2/(5^2) or (2/5)^2 .
• 9 years agoHelpfull: Yes(0) No(4)
• a=2/5
  r=2/5
  so
  sum of infinite GP is=2/5(1/1-2/5)=2/3
• 2 years agoHelpfull: Yes(0) No(0)