A Museum decorated with bunch of lights and those lights glow for every 13 seconds. How many times did it glow between 1:57:58 and 3:20:47??

A.380
B.381
C.382
D.383

• find out difference between both times that is 1:22:49 total no of seconds that is 4969 then divided by 13 so the ans is
  382
• 8 years agoHelpfull: Yes(10) No(2)
• 1:22:49 to 3:20:47 is total 4969 sec/13 is 382 but the ans is 383 because at 1:57:58 min they will glow 1st time then they will glow after every 13 sec .. so the ans is 382+1=383
• 8 years agoHelpfull: Yes(8) No(4)
• 1:57:58=7078 sec..........(1)
  3:20:47=12047 sec............(2)
  sub. 2-1=-4969 then devied by 13 ===382.23 so ans is 382
• 8 years agoHelpfull: Yes(3) No(2)
• Confused...is it 382 or 383??
  
• 8 years agoHelpfull: Yes(2) No(0)
• added 2 min and 02 sec on both side
  then you get 1 hr:22m:49s exactly then converted into sec
  and divided by 13 you get 382
• 8 years agoHelpfull: Yes(1) No(0)
• but answer given is 383....i am also getting 382.
• 8 years agoHelpfull: Yes(1) No(1)
• d
  the diff btween both times in sec is 4946/3 =382
  but at 1:57:58 it glows first time
  
• 8 years agoHelpfull: Yes(1) No(0)
• 383
  i.e the answer
• 8 years agoHelpfull: Yes(1) No(0)
• find diff btw two times that is 4969 then divided by 13
  ans : 382
  
• 8 years agoHelpfull: Yes(1) No(0)
• 383 TIMES.
  
• 8 years agoHelpfull: Yes(1) No(0)
• diff between 3:20:47 & 1:57:58 is 1:22:49
  converting it to seconds = 4969
  dividing 4969 by 13 we get 382
• 8 years agoHelpfull: Yes(0) No(1)
• time=2 min abd 2 sec+60 min+20 min &47 sec so total sec 122+3600+1247
  4969/13=382(B)
• 8 years agoHelpfull: Yes(0) No(1)
• apprxtmly 382.69 so it is 383
• 8 years agoHelpfull: Yes(0) No(3)
• 1:57:58=7078 secs(1*3600+57*60+58)
  3:20:47=12047 secs(3*3600+20*60+47)
  difference=4969 secs
  light glows for 13 secs
  for 4969 it glows for 382 times
• 6 years agoHelpfull: Yes(0) No(0)
• 1:57:58=7078 sec..........(1)
  3:20:47=12047 sec............(2)
  sub. 2-1=-4969 then devied by 13 ===382.23 so ans is 382
• 2 years agoHelpfull: Yes(0) No(0)