in how many ways can the letter of english alphabet be arranged so that there are seven letters between the letter A and B and no letter is repeated

• Answer is 24c7*7!*2
  Reason: REMAINING alphabets excluding A ,B=24
  7 alphabets should be arranged in btwn A & B,means 24c7 combination or selection are possible=> A*******B = 24c7 ways.
  now the selcted alphabets themselves can b arranged in 7! ways =>24C7*7!
  Finally they said in between A and B So another possible which dobles the count is B*******A =24c7*7!
  SO, ans is 24c7*7!*2
• 8 years agoHelpfull: Yes(10) No(2)
• 24p7*2!*18!
• 8 years agoHelpfull: Yes(7) No(3)
• 7 alphabets are to be placed in btw A and B.
  Numbers of ways are=24*23*22*21*20*19*18.
  Since A and B are fixed so remained alphabets are 24.
• 8 years agoHelpfull: Yes(5) No(5)
• Ans is 24p7*2!*18! , it is because excluding A and B we have 24 letters and we have to find arrangements of 7 letters , it is multiplied by 2 because A and B can be arranged in 2! ways and again multiplied by 18 because 26-2-7+1 =18
• 8 years agoHelpfull: Yes(4) No(0)
• 36*24! Is the correct answer , tally with anyone
• 8 years agoHelpfull: Yes(4) No(0)
• 24c7*7!*2!
• 8 years agoHelpfull: Yes(2) No(0)
• 2*7!*18! -ans
  we will consider 2*7! as one box and internally we will arrange it in this way now we will be left with 18 alphabet including the box so the way to arrange them will be 18!
  
• 8 years agoHelpfull: Yes(2) No(0)
• 24c7
  remaining numbers 24 and places 7
• 8 years agoHelpfull: Yes(0) No(4)