The difference between two no is 9 and the product of the two is 14. What is the square of their sum?

• x-y= 9
  xy= 14
  (x+y)^2= (x-y)^2+4xy= 81+ 4*14=81+ 56= 137
  
• 9 years agoHelpfull: Yes(11) No(1)
• given,
  a-b=9,ab=14
  as we know,
  (a-b)^2=(a+b)^2-4ab
  9^2=(a+b)^2-4*14
  so, (a+b)^2=137
• 9 years agoHelpfull: Yes(3) No(0)
• 
  x-y=9
  xy=14
  
  81=x^2+y^2-28
  
  109=x^2+y^2
  
  So,(x+y)^2=x^2+y^2+2xy
  
  109+28=137
• 9 years agoHelpfull: Yes(1) No(0)
• x-y = 9
  (x-y)^2 = 9^2
  x^2 + y^2- 2.x.y = 81
  x^2 + y^2 = 81 + 2.14
  x^2 + y^2 = 81+28
  x^2 + y^2= 109
• 9 years agoHelpfull: Yes(0) No(1)
• keep it simple :)
  given=> a-b=9 , ab=14
  (a-b)^2=9*9=81
  (a^2 + b^2 -2ab)+2ab=a^2 +b^2=81+(2*14)=109
  but
  we need to find (a+b)^2
  => (a^2+b^2)+2ab=109+(2*14)=109+28=136
  
  SO 136 is d answer..!! :)
  
• 9 years agoHelpfull: Yes(0) No(1)
• 137 is the correct answer
  
• 9 years agoHelpfull: Yes(0) No(0)
• sorry 137 is the correct answer
  (x+y)^2= 109+28
  = 137
• 9 years agoHelpfull: Yes(0) No(0)
• given
  a-b=9
  ab=14
  (a+b)^2=(a-b)^2+4ab
  
  
• 9 years agoHelpfull: Yes(0) No(0)
• given
  a-b=9
  ab=14
  (a+b)^2=(a-b)^2+4ab
  =9^2+4*14
  =81+56
  =137
• 9 years agoHelpfull: Yes(0) No(0)