In a mixture of petrol and kerosene, petrol is only 99 litres. If this same quantity of petrol would be presented in another mixture of petrol and kerosene where total volume would be 198 litres less than the actual mixture then the concentration of petrol In the present mixture would have been 13.33% point less than that. What is the concentration of petrol in actual mixture?
Options:
1. 20%
2. 16.66%
3. 26.66%
4. 8.33%

• Ans: 20%
  Solution:
  Petrol kerosene Total Volume
  99 x (x+99)
  Petrol kerosene Total volume
  99 (x-198) (x-99)
  now; [99/(x-99)*100]-[99/(x=99)*100]=13.33
  by simplifying [9900*198/(x^2-99^2)]=40/3
  x^2-99^2=147015 147015 can be written as (99^2*15)
  Therefore x^2= 99^2*16
  x=396.
  now; [ 99/(99+396)] *100= 20%
• 8 years agoHelpfull: Yes(8) No(1)
• Ans: 26.66%
  Solution:
  let x is the amount of petrol.
  then
  (x*100)/198=13.33
  x=26.3934
  now same amount of petrol is in 99 liters also.
  so the percentage in actual mixture is
  (26.3934*100)/99
  =26.66%
  
  
• 8 years agoHelpfull: Yes(2) No(1)
• ans is 16.66%
• 8 years agoHelpfull: Yes(1) No(4)