There are three runners Tom, Dick and Harry with their respective speeds of 10kmph, 20kmph and 30kmph they are initially at P and they have to run between the two points P and Q which are 10 km apart from each other. They start their race at 6 am and end at 6 pm on the same day. If they run between P and Q without any break, then how many times they will be together either at P or Q during the given time period?
Options:
1. 5
2. 7
3. 4
4. 12

• Tom, dick and harry will meet at P after every 2 hours, so in that case after every 2 hours they will meet.
  Now at 6 a.m also they all are together. So the answer will be 7.
• 8 years agoHelpfull: Yes(23) No(2)
• T,D,H start at 6 am at P
  At 7'O clock
  T will be at Q(10kmph)
  D will be at P(20kmph)
  H will be at Q(30kmph)
  At 8'O clock
  T will be at P
  D will be at P
  H will be at P
  Thus for every two hours they meet at P.
  So for 12 hours they meet for 6 times and if the first meet at starting point is included.6+1=7 is the answer.
• 8 years agoHelpfull: Yes(16) No(0)
• TAKE LCM OF 3 SPEED ,answer is 12
• 8 years agoHelpfull: Yes(3) No(21)
• 7. Three of them meet at every 2 hrs.
• 8 years agoHelpfull: Yes(2) No(4)
• how they meet every 2hrs?
  
• 8 years agoHelpfull: Yes(2) No(2)
• 2.) 7 because in 6a.m to 6 p.m there are 12 hours so in 12 hours they meet at even hours 2,4,6,8,10.12
  i.e. 6 and +1 at 0th time at the beginning i.e 7 so answer is 7
• 8 years agoHelpfull: Yes(2) No(0)
• Answer = 4. they meet 4 times in 6 hours
  they are together at p initially. this is first meeting.
  then they meet every 2 hours. , so in 6 hours they meet 3 times.
  3+1 = 4
• 8 years agoHelpfull: Yes(0) No(10)
• after 2 hrs they will be at the same point either at p or q , if first meeting is also considered then total number of meetings = 1+3, so ans. will be 4.
  
• 8 years agoHelpfull: Yes(0) No(7)
• Tom-10kmph -- 12 times
  Dick-20kmph --- 24 times
  harry-30kmh -- 36 times
  
  6am-6pm ..........
  
  The numbers which divides 12,24 and 36 are -- 2,3,4,6,12
  So ans is 5
  
  
• 8 years agoHelpfull: Yes(0) No(4)