jake i faster than paul each walk 24 km the sum of their speeds is 7kmph and t he sum

Ans is 4.
Let the speed of jake b x and paul be y
then x+y=7
&
24/x+24/y=14
On solving as jake = 4 as it is faster and paul is 3
9 years agoHelpfull: Yes(3) No(2)
let jake speed be x, then paul's speed = (7-x)
so, (24/x)+(24/(7-x)) =14
therefore x=4
9 years agoHelpfull: Yes(1) No(0)
each walk =24km;
sum of speed =j+p=7km/hr
j=p-7;
now sum of time =14hr;
24/j+24/p=14;
24((j+p)/jp)=14;
24*7=14jp {bcoz j+p=7};
12=jp;
12=j(j-7);
j^2-7j-12=0;
j^2-4j-3j-12=0;
j(j-4)-3(j-4)=0;
(j-4)(j-3)=0;
j=3 or 4 but if j=3 thenp=4 which is not possible
so j=4 ans....
9 years agoHelpfull: Yes(0) No(0)
jakes speed=x
paul speed =y

x+y=7
so speed can b in the ratio
1:6 or 6:1
2:5 or 5:2
4:3 or 3:4
total time taken = let us take 1:6 as 1st case
so 24/1+24/6= 29 which is not equal to the total time given
so try all options same way, u will get 4:3 appropriate
hence speed of jake is 4 km/h
9 years agoHelpfull: Yes(0) No(0)

jake i faster than paul each walk 24 km. the sum of their speeds is 7kmph and t he sum of times taken by them is 14 hrs.then jake speed is equal to