Q. what will be the value of x+y ?

1. (x^2-y^2)/x-y=8.
2. (x+y)^2=64

• RAJKUMAR SAINI.
  your ans. is wrong. it should be only 1st statement fulfill the condition.
  from 2nd condition there are two value (+8) & (-8). that's not clear what is the value,cuz there are two values from 2nd equation.
  SO PERFECT ANSWER IS (A) only 1st alone fulfill the condition.
• 9 years agoHelpfull: Yes(32) No(7)
• only we have to find out the value of x+y whatever it is so
  1)x+y=8
  2)x+y = +8,-8
  so answer can be given by any of the statement
  
• 9 years agoHelpfull: Yes(8) No(12)
• Mr. Anup is it asked in the question any unique value.. No..
  They asked what is the value of x+y only this.. So 1st can easily be understood nd 2nd give values +8,-8 but it gives the value and it gives the value all knows it is a quadratic equation so value can unique but it gives value.. So both r sufficient to give the answe
• 9 years agoHelpfull: Yes(8) No(1)
• This is data sufficiency ques only 1st statement is sufficient. 2nd statement is giving +- 8 as ans in data sufficiency ans should be unique.. So option A will be the ans
• 9 years agoHelpfull: Yes(6) No(4)
• As (x^2-y^2)= (x+y)(x-y)
  so, (x+y)(x-y)/(x-y)=8
  (x+y)=8
  For 2. (x+y)^2=64
  (x+y)=(64)^1/2=8
  Thus, (x+y)=8 Ans.
• 9 years agoHelpfull: Yes(4) No(5)
• can be solved by both....
  1.because x^2-y^2=(x+y)(x-y) so x+y=8 .
  2.(x+y)^2=64 ,so x+y=8.
  correct me if i m wrong..
  
• 9 years agoHelpfull: Yes(3) No(11)
• from first equation we get x+y=8 (confirmed value)
  
  but from from equation 2nd we get x=y=+8,-8 (confused value) so from this we cant givethe answer
  
  bt from First we can get confirmed value of x=y=8
  
  So only equation first is suitable to give the answer.
• 9 years agoHelpfull: Yes(3) No(2)
• (x^2-y^2)/x-y=x+y
  given x+y=8
  so ans is 8
  checking for statement 2
  (x+y)^2=8^2 = 64
  verified.
• 9 years agoHelpfull: Yes(2) No(0)
• 1 (x^2-y^2)/x-y=8
  (x+y)(x-y)/(x-y)=8
  (x+y)=8
  2 (x+y)^2=64
  x+y=+8,-8
• 9 years agoHelpfull: Yes(1) No(0)
• eq 1. (x-y)(x+y-8)=0 and x!=y means x+y=8
  eq 2 . (x+y)(x+y)=64=>x+y=8,-8
  
  
  so from both eq x+y=8
• 9 years agoHelpfull: Yes(1) No(0)
• either one or two both can give ans indiv.
• 9 years agoHelpfull: Yes(1) No(0)
• From statement 1 we can conclude dat x+y =8. From 2 we conclude dat x+y is either 8 or -8.and according to data suffiency we search for unique values which we are only gettng from equation 1 nd nt from 2.So option A.
• 9 years agoHelpfull: Yes(1) No(0)
• This is very confusing rather than getting correct answer.. I m getting confused ..be it any question ..I would like to request our admin to kindly post the correct answer in the end
• 8 years agoHelpfull: Yes(1) No(0)
• First option alone can give the answer.
  As 2nd opt. gives two ans +/-8.
• 9 years agoHelpfull: Yes(0) No(0)
• Case-1 (x^2-y^2)= (x+y)(x-y)
  (x+y)(x-y)/(x-y)=8
  (x+y)=8
  Case-2
  (x+y)^2=64
  (x+y)=(64)^1/2=+/_8
  in this case we can't determine the unique solution
  So case 1 is sufficient to answer So ans is A.
  
• 9 years agoHelpfull: Yes(0) No(0)
• 8
  (x^2-y^2)/x-y=8 => (x+y)(x-y)/x-y=8 => (x+y)=8
• 9 years agoHelpfull: Yes(0) No(1)
• 8 is the ans
  
• 9 years agoHelpfull: Yes(0) No(1)
• Statements (1) and (2) TOGETHER are NOT sufficient to answer the question.
  because both the equations are same 1.(x+y)(x-y)/(x-y) =8 ==> (x+y)=8
  2. (x+y) = 8 (taking square root of both side.)
  and we have (x+y)= 8 so we have many combination of this equation like (7,1),(6,2)(4,4)
  we can not conclude the unique value of x+y.
• 8 years agoHelpfull: Yes(0) No(2)
• Correct option is : D
  In statement 1, we are getting x+y=8 , but this is only true if x!=y, otherwise division is not valid.
  In statement 2, we cannot determine unique value of x+y=+8,-8.
• 7 years agoHelpfull: Yes(0) No(0)
• Answer will be 1 . They asked x+y so value must be unique .
  in statement we get a unique value 8 but in second statement we get +8 ,- 8 .
  So second statement cannot be true.
  Ans is 1
• 2 years agoHelpfull: Yes(0) No(0)