find the value of a,b,c,d,e (68-a)(68-b)(68-c)(68-d)(68-e)=725

• Take the lcm of 725 you get these values 5,5,29
  So we can write 725 as
  1*(-1)*5*(-5)*29=725
  now (68-a)(68-b)(68-c)(68-d)(68-e)=725
  68-a=1 so a=67
  68-b=-1 so b=69
  68-c=5 so c=63
  68-d=-5 so d=73
  68-e=29 so e=39
  
• 9 years agoHelpfull: Yes(15) No(0)
• Firstly we have to factor 725 which gives 29 X 5 X 5 Bt total variable is 5 n all are distinct one 5 will be negative n two more needed which will be 1 and -1 suits n don't disturb this equation so it will be 1,-1, -5,5,29....a,b,c,d,e are in ascending order so a will be minimum When it will equals to max no. E.g 68-a= 29 gives min value of a.....n so on..... At last result will be 39,63,67,69,73....thanks
• 9 years agoHelpfull: Yes(2) No(1)
• a=97,b=73,c=d=67,e=63
• 9 years agoHelpfull: Yes(0) No(3)