george does 3 5th of the work in 9 days then he calls in paul and they finish the work

Ans. 30 Days

3/5 unit work is done by George in 9 days, so he will complete the whole work in 15 days
i.e. 9*(5/3) = 15.
Suppose work as 1 Unit.
then remaining work is 1 - 3/5 = 2/5.

lets Paul can do the work in x days,
so 1 day's both work= (x+15)/15x

means they will complete the work together in 15x/(x+15) days

2/5 unit work have to be completed by both
so,

2/5*(15x/(x+15))=4

x=30.
9 years agoHelpfull: Yes(7) No(0)
george does 3/5 unit work in 9 days.and george does 3*4/9*5=4/15 unit work in 4 days.hence total work done by george is 4/15+3/15=13/15, rest work 1-13/15=2/15 is done by paul in 4 days. so paul will take to finish the work alone in 4*15/2=30 days
9 years agoHelpfull: Yes(2) No(0)
George can do a 3/5 in 9 day so he will take 15 day to complete a work but he and Paul can finish same work in 4 day
let the work X then capacity of George is X/15
then capacity of Paul and George is X/4
so Paul capacity is( 60*X)/11
so Paul can finish X work in 60/11 days
9 years agoHelpfull: Yes(1) No(3)
3/5w->9day
w=(9*5)/3=15day george take to complete whole work w
P+G ,2/5w->4day
so whole work to be done by both in (4*5)/2=10day
paul efficiency to complete whole work=1/10-1/15=1/30 so time taken=30days
9 years agoHelpfull: Yes(1) No(0)
as george itself will complete work in 15 days
both two will complete works in 10 days

30 days paul will complete his work
9 years agoHelpfull: Yes(0) No(0)
(9+4)/15 + 4/x = 1
if we solve this we can get 30 days
8 years agoHelpfull: Yes(0) No(0)

george does 3/5th of the work in 9 days,then he calls in paul and they finish the work in 4 days.how long will paul take to finish the work alone?