The average temperature of June, July and August was 31 degrees. The average temperature of July, August and September was 30 degrees. If the temperature of June was 30 degrees, find the temperature of September (in degrees).

option:
a.25
b.26
c.27
d.28

• c.27
  
  June+July+August=3*31=93.......(1)
  July+august+Sept=3*30=90........(2)
  June=30
  
  Hence, putting june =30 in equ 1
  
  July+August=63
  
  putting in 2nd equ.
  63+Sept=90
  
  hence, Sept=27
• 9 years agoHelpfull: Yes(16) No(0)
• June + July + August = 93 ( Total )
  Juky + August + Sept. = 90 (Total)
  ------------------------------------------
  (Minus)
  June - Sept. = 3
  30 - Sept = 3
  Or, 30-3=Sept which will be 27.
• 9 years agoHelpfull: Yes(5) No(0)
• (june+july+aug)/3=31
  (july+aug+sep)/3=30
  given that
  june=30
  let july=31,aug=32
  now,(31+32+sep)/3=30
  sep=90-63
  sep=27
• 9 years agoHelpfull: Yes(2) No(0)
• june+july+agust=93--------(1)
  july+agust+sept=90------------(2)
  (1)-(2)=>june-sept=3
  given june=30
  sept =30-3=27
  
  
• 9 years agoHelpfull: Yes(2) No(0)
• June + july + august = 31x3 = 93
  given, june =30
  thus, july+august=93-30=63
  
  now given , july + august +sept = 30x3 = 90
  so,
  sept= 90 - (july+august) = 90 - 63 = 27
  
  thus (C)
• 9 years agoHelpfull: Yes(2) No(0)
• June+July+august=31*3=93
  June+July+August+September= 30*4=120
  Temp of September= 120-93=27
• 9 years agoHelpfull: Yes(2) No(0)
• answer is c.27
  june +july+aug=31(30)=93
  july+aug+sep=30(3)=90
  gn:june=30
  in 1 st eq july +aug=93-30=63
  in 2nd eq 63+sep=90
  sep=90-63=27
• 9 years agoHelpfull: Yes(2) No(0)
• june+july+august=93
  june+july+september=90
  now subtract above two eqaution we get
  june-september=3
  now value of temp in june is=30
  so after puting the value of june we got tep of september is eqaul to 27 i.e answer
• 9 years agoHelpfull: Yes(2) No(0)
• let take june as jn;july as jl;august as a;september as s;
  (jn+jl+a)/3=31
  given jn=30;
  jl+a=93-30=>jl+a=60;
  (jl+a+s)/3=30;
  s=90-(jl+a)=>90-63
  september temperature is 27
• 9 years agoHelpfull: Yes(2) No(0)
• june+july+august=3*31=93
  july+august+september=3*30=90
  and june=30
  so,
  july+august=93-30=63
  
  so,
  july+august+september=90
  63+september=90
  september=90-63=27
• 9 years agoHelpfull: Yes(1) No(0)
• 27 degrees because (june+july+aug)/3=31,(july+aug+sep)/3=30 solving we get 27
• 9 years agoHelpfull: Yes(1) No(0)
• (jun(=30)+jul+aug)/3=31 => jul+aug= 31*3-30=63... (jul+aug+sep)/3=30 => sep = 30*3 - (jul+aug) = 90-63=27
• 9 years agoHelpfull: Yes(1) No(0)
• 27 is correct answer
  
  
• 9 years agoHelpfull: Yes(1) No(0)
• c.27
  June+July+Aug=93
  June =30
  July+Aug=63
  July+Aug+Sep=90
  Sep=27
• 9 years agoHelpfull: Yes(1) No(0)
• June + July + August = 31*3 = 93 -----------( 1 )
  July + August + September = 30*3= 90 --------------(2)
  june = 30
  
  Now eqvate equ 1 and 2 we get
  June - Sep = 3 -----------------( 3 )
  
  Then substitute the value of June=30
  In the equ (3)
  Now we get Sep = 27
  
  
  Ans is 27
• 9 years agoHelpfull: Yes(1) No(0)
• total temp. of (june+july+aug)=3*31
  =93
  total temp. of (july+aug+sept) = 3*30
  hence, temp of sept. 30-3= 27
• 9 years agoHelpfull: Yes(1) No(0)
• 27
  93=june+ju+au
  90=July+au+se
  ju+au=63 then
  sep=90-63=27
  
• 9 years agoHelpfull: Yes(1) No(0)
• C.27 is answer
• 9 years agoHelpfull: Yes(1) No(0)
• (30+JA)/3 = 31
  JA =63
  
  so,
  (63+sep)/3 = 30
  sep = 27
  
• 9 years agoHelpfull: Yes(1) No(0)
• june ,july,august =93
  july,august,sep=90
  so july+august=63 and sep= 90-63=27
• 7 years agoHelpfull: Yes(1) No(1)
• (june+july+aug)/3=31-----------(1)
  (july+Aug+Sep)/3=30------------(2)
  
  sub equation (2) from equation (1),
  we get,
  June - Sep=3 --------(3)
  given, june=30.
  put the value in equation 3
  we get,
  sep=27.(Ans)
• 5 years agoHelpfull: Yes(1) No(0)
• june + july+ august=(3*31)=93.....(1)
  given, july + august +sep=(30*3)=90....(2)
  as per avg=sum/no:of
  i.e,
  eq(1)
  30+(july+aug)=93
  july+aug=93-30=63
  in equ(2)
  63+sep=90
  sep=90-63=27
• 5 years agoHelpfull: Yes(0) No(0)