A sum of money is borrowed and paid back in two annual instalments of Rs. 882 each allowing 5% C.I. The sum borrowed was:

• it is an compound interest
  in 1st year it is 882
  in 2nd year 882+5%0f 882
  so in first year is 882
  in 2nd year is 926.1
  total in 2 year is 1808.1
  so it is an amount now if u substitute in c.i formula
  1808.1=p(105/100)2
  p=1640
  so answer is 1640
• 8 years agoHelpfull: Yes(4) No(0)
• From question we have
  P(1+r/100)^n=882.
  P=882*(20/21)^2
  P=882*400/441. So P=800.
• 8 years agoHelpfull: Yes(3) No(4)
• The sum borrowed
  
  = Present Worth of Rs.882 due 1 year hence + Present Worth of Rs.882 due 2 year hence
  
  =882(1+5100 ) 1 +882(1+5100 ) 2 =882(105100 ) +882(105100 ) 2 =882(2120 ) +882(2120 ) 2 =882×2021 +882×20×2021×21 =42×20+42×20×2021 =840+2×20×20=840+800=1640
  
  i.e., The sum borrowed = Rs.1640
• 8 years agoHelpfull: Yes(3) No(3)
• let sum borrowed be x
  instalment for every year is 882
  in one year sum=x(1+5/100)=1.05x
  in second year sum=1.05x(1.05)
  1.05x+1.05x(1.05)=(882*2)=1764
  x(1.05)(1+1.05)=1764
  x=819.5
  
• 8 years agoHelpfull: Yes(1) No(0)
• Actually it include two annul installment..
  
  So ..
  2*882=p(1+5÷100)^2
  So p is 1600.
• 8 years agoHelpfull: Yes(0) No(2)
• please sumone tell the correct solution for this .....
  
• 8 years agoHelpfull: Yes(0) No(0)
• for 2 consecutive instalments with 5% per annum they recieve total 882+882=1764
  and effective interest in these two years is (x+y+xy/100)
  at here x=y=5
  then (x+y+xy/100)=10.25
  110.25 * borrowed cost =1764
  B.C= (1764/110.25)*100=1600
  
• 8 years agoHelpfull: Yes(0) No(0)
• 1640 is write answer
  
• 7 years agoHelpfull: Yes(0) No(0)