we have an equal arms two balance and need to weigh objects with integral in the range 1 to40kilo grams. we have a set of standard weights and can place the weigts in any pan.i.e some weigts can be in a pan with objects and some weigts can be in other pan.the minimum number of standard weigts required is?

• 4 weights
  
  1, 3, 9, 27 Kg. weights are sufficient to measure from 1 kg. to 40 kg.
• 9 years agoHelpfull: Yes(9) No(6)
• ans.=6.
  for measuring 1 to 7 kgs there will be 3 weights i.e.1,,2,4
  and now for measuring 8 to 15 kgs there will be another weight add is 8
  by taking weight 16 kg there will be only 31 kgs that we can measure by this
  hence 6 weights are required i.e.-1,2,4,8,16,32.
• 9 years agoHelpfull: Yes(2) No(4)
• the answer is 2
  
  
• 9 years agoHelpfull: Yes(1) No(3)
• the answer is 1
• 9 years agoHelpfull: Yes(0) No(5)
• ans 4
  
  3,9,27,32
• 9 years agoHelpfull: Yes(0) No(3)
• .5*48*14+14*50+.5*50*50=2286 is right
• 9 years agoHelpfull: Yes(0) No(2)
• ans is 4 because we are using power of 3 as 3^0 3^1 3^2 3^3
• 9 years agoHelpfull: Yes(0) No(0)
• 4 minimum we use power of 3 !
  Hence solution is=3^0+3^1+3^2+3^3
  =1+3+9+27=40
  Hence using these 4 values we can measure any weight b/w 1&40 !!
  
  
• 9 years agoHelpfull: Yes(0) No(0)