Suppose there is an outlet which is pouring water at a constant rate and is able to fill a swimming pool in nine hours. There is another outlet that is able to fill the pool in five hours. If we open both the outlets and let them pour the water together

How many hours will it take to fill the pool ?

• 1/9+1/5=14/45 gives 45/14 i.e 3.214 hours to fill the pool completely
• 9 years agoHelpfull: Yes(15) No(0)
• total work=1/9+1/5=14/45 so reqired time=45/14=3.21 hours
• 9 years agoHelpfull: Yes(12) No(0)
• 1/9+1/5=3.2
• 9 years agoHelpfull: Yes(2) No(0)
• (9*5) / (9+5) = 45/14 =3.21 hours
• 9 years agoHelpfull: Yes(2) No(0)
• total work=ab%(a+b)=9*5%(9+5)=45%14=3.21hrs
  
• 9 years agoHelpfull: Yes(2) No(0)
• (9*5)/(9+5) =45/14
• 9 years agoHelpfull: Yes(0) No(0)
• 3.214 hours will take to fill
• 9 years agoHelpfull: Yes(0) No(1)
• 45/14=3 3/
  14
• 9 years agoHelpfull: Yes(0) No(2)
• time required= 9*5/9+5=3.214 hrs
• 9 years agoHelpfull: Yes(0) No(0)
• 1/9+1/5=14/45
  therefore 45/14 hours
• 9 years agoHelpfull: Yes(0) No(0)
• Let take capacity of tank=900 L
  First outlet van fill the 900 L in 9 hours.
  => In 1 hour it can fill 100 litres.
  For second outlet, It can fill 180 L in 1 hour(900/5=180)
  Now both the outlets are open,
  For 1st hour= 100L+180L=280 L
  For second hour=280+280=560
  For 3rd hour=560+280=840L
  Now 60 Litres have to fill.(900-840=60)
  Both outlets can fill 180 L in 1 hour.
  Time required them to fill 60L =20 mins.
  So, Total time required fill the whole tank=3.20 Hours.
• 6 years agoHelpfull: Yes(0) No(0)