a tree of height 36m at the edge of the reoad broke at a certain height, it fell in such a way that it stop touch the other edge of the road. if the breadth is 12 m, then what is the height at which the tree broken

• If tree is broken then it forms a right angled triangle.
  Let the height of broken tree =y
  and length of broken part=x
  now, x + y = 36
  x^2 - y^2=144
  (x+y)(x-y)=144
  36(x-y)=144
  x-y=4
  =>x=20
  y=16
• 9 years agoHelpfull: Yes(12) No(0)
• let the broken tree height be 36-x ,the other one will be x
  so perpendicular =36-x ,hypotenuse =x and base =12 m
  no using Pythagoras theorem . x^2 = (36-x)^2 + 12^2
  --->>> X^2 =1296 +X^2 -72x+144
  >>>>>72x = 1440
  >>>>> x=20 m answer and height of broken tree is 16m
• 9 years agoHelpfull: Yes(3) No(0)
• let height of broken part be x . then remaining part = 36-x.
  now pythagoras theorem :- 36^2= (x-36)^2 + 12^2
  on solving this we will get x=20
  ans = 36-20=16 m
• 9 years agoHelpfull: Yes(2) No(2)
• height=12.44m
• 9 years agoHelpfull: Yes(1) No(7)
• let the height at which tree is broken(ground to broken part)=x
  height of remaining=36-x
  (36-x)^2=x^2+12^2
  x=2.25m
• 9 years agoHelpfull: Yes(1) No(5)