what is the least value of n for which 99^n begins with 8.
A) 11
b)10
c)9
d) such value not exist for any value for n

• 99^1=99
  99^2=9801
  99^3=970299
  99^4=96059601
  notice one thing power is 1 number start with 99
  power =2 then number start with 98
  power =3 then number start with 97
  and so on
  power =4 then number start with 96
  power =5 then number start with 95
  power =6 then number start with 94
  power =7 then number start with 93
  power =8 then number start with 92
  power =9 then number start with 91
  power =10 then number start with 90
  power =11 then number start with 89
  so option A is correct
  
• 9 years agoHelpfull: Yes(57) No(0)
• 99^11 begins with 8. N=8
• 9 years agoHelpfull: Yes(4) No(1)
• value of n would be 11
  that start number will start from 8
• 9 years agoHelpfull: Yes(2) No(0)
• In a more traditional way, this problem can be solved like below.
  99(100 - 1) = 9900-99= 9801
  9801(100 - 1) = 980100-9801= 971299
  971299(100 - 1) = 97129900 - 971299 = 96157601
  .....
  .....
  Just observe the pattern, 98, 97, 96, .... for power of 2, 3, 4, .... So for 90 the power could be 10. So for 11, you get a number starts with 8. ans.(a)
• 9 years agoHelpfull: Yes(1) No(0)
• 9
  n=11,12,13,14,15,16,17,18,19 (there will also b another values like 20,21... but it ask minimum )
• 9 years agoHelpfull: Yes(0) No(1)
• such value not exit for any value of n
• 9 years agoHelpfull: Yes(0) No(4)
• great answer @abhishek
• 9 years agoHelpfull: Yes(0) No(0)
• good explanation @ abhishek
• 9 years agoHelpfull: Yes(0) No(0)
• (A) 11 is the right answer because the starting digit is 8
• 8 years agoHelpfull: Yes(0) No(0)