What is the value of 62th term for the following sequence j1=139/3,j2=-19……………j(k-1 )+j(k-2)=jk.

• correct answer is -19
• 8 years agoHelpfull: Yes(5) No(1)
• bro the last part of question was ,,for k>=3, j(k-1)- j(k-2)=j(k)!!
  
• 8 years agoHelpfull: Yes(2) No(0)
• i think answer 139/3 is right answer
• 8 years agoHelpfull: Yes(2) No(3)
• I think question was sum upto 62 terms. ATQ it, upto 60th term all terms cancel out & hence the answer will be -19-163/3=-196/3 ans.
• 8 years agoHelpfull: Yes(1) No(1)
• anyone plz xplain in details..
• 8 years agoHelpfull: Yes(0) No(0)
• correct answer is 139/3
• 8 years agoHelpfull: Yes(0) No(1)
• -19 is the right answer
• 8 years agoHelpfull: Yes(0) No(0)