When 3 dies are rolled together, what is the probability of getting a sum of 10?

• Total Sampl Space is 6^3=216
  and desired event is
  ((1,6,3) = 6 ways
  (1,5,4)= 6 ways,
  (2,6,2)= 3 ways
  ,(2,5,3)=6 ways
  ,(2,4,4) = 3 ways
  
  (3,4,3)= 3 ways
  Total 27 ways so desire d probability is 27/216
• 9 years agoHelpfull: Yes(12) No(1)
• 1/8
  
  Total outcomes with 3 dice= 6*6*6=216
  Events with sum of 10 are (1,3,6) (1,4,5) (1,5,4) (1,6,3) (2,2,6) (2,3,5) (2,4,4) (2,5,3) (2,6,2) (3,1,6) (3,2,5) (3,3,4) (3,4,3) (3,5,2) (3,6,1) (4,1,5) (4,2,4) (4,3,3) (4,4,2) (4,5,1) (5,1,4) (5,2,3) (5,3,2) (5,4,1) (6,1,3) (6,2,2) (6,3,1)
  Total=27
  So Probability=27/216= 1/8
• 9 years agoHelpfull: Yes(2) No(0)
• when 3 dice are rolled
  if sum is between 3 to 8 then no of posibilites is n-1c2
  if sum is 10 or 11 it is 27
  if sum is 9 or 12 it is 25
  greater than 13 it is 20-nc2
  so probability is 27/216=1/8
• 9 years agoHelpfull: Yes(1) No(0)
• To be able to roll a 10 with 3 dice, the first 2 dice must give a value between 4 and 9 (probability of 3/4), in which case there is a 1/6 chance that the third die will make the total 10. So, the overall probability is 3/4x1/6=1/8.
• 9 years agoHelpfull: Yes(0) No(1)