How many combinations of numbers less than 8 make their sum 8 repetation of numbers is allowed

without zero-

8 digit no, =11111111
7 digit no.= 1111112,1111121,1111211........= total 7 numbers
6 digit no. = 111113,111131...........= total 6 numbers
5 digit no.= 11114,11141.................=total 5 numbers
4 digit no.= 2222,1115,1151,1511,5111= total 4 numbers
3 digit no.= 116,161,611,224,242,422,332,323,233= total 9 numbers
2 digit no. = 44,17,71,26,62,35,53 = total 7 numbers.

now total possible numbers are (without zero) = 1+7+6+5 +4+9+7=39 may be
8 years agoHelpfull: Yes(6) No(6)
20 (if zero (0) is not considerd as a number)
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17,26,35,44
116,125,134,224,233
1115,1124,1133,2222,2213
11114,11123
111113,111122
1111112
11111111
8 years agoHelpfull: Yes(2) No(2)
((1,7) (7,1) (6,2) (2,6) (5,3)(3,5) (4,4) =7 ans
8 years agoHelpfull: Yes(1) No(4)
if you form a number with the help of zero (0) digit as well then there will be lot of number can be formed.
8 years agoHelpfull: Yes(0) No(0)
srry 4 digit no. =total 5 numbers
so total will be 40 numbers
8 years agoHelpfull: Yes(0) No(0)
but in combination (1,7)=(7,1)
both are same combination
so we count 1 not 2
8 years agoHelpfull: Yes(0) No(0)
ADMIN CAN U PLS TELL THE CORRECT ANSWER....IT IS BIT CONFUSING
AS SOON AS POSSIBLE
8 years agoHelpfull: Yes(0) No(0)
117 ans
8 years agoHelpfull: Yes(0) No(0)
0,1,2,3,4,5,6,7,8
(1,7)=2! ways
(0,8)=2!ways
(2,6)=2! ways
(3,5)=2!ways
(4,4)=1 way
2+2+2+2+1=9
8 years agoHelpfull: Yes(0) No(1)
i think 115
8 years agoHelpfull: Yes(0) No(0)

How many combinations of numbers less than 8 make their sum=8 (repetation of numbers is allowed)