A teacher set a ques ppr consist of 8 question of total 40 marks such that each question contains minimum two marks and integer number of marks. In how may ways this can be done?
a)48C7 b)31C7 c)32C7 d)40C8

• 2no is sure to divide b/w 8 ques so no which we need to divide is only=40-(8×2)=24
  and by the therom if we want to divide n different thing in r part then formula is=n+r-1Cr-1
  So ans is =24+8-1C8-1=31C7
• 9 years agoHelpfull: Yes(26) No(0)
• (x1+2)+(x2+2)+(x3+2).............(x8+2)=40
  hence x1+x2+x3+.........x8=24....
  Apply non negative integer formula 24+8-1C8-1= 31C7
• 9 years agoHelpfull: Yes(11) No(0)
• d)40 C8 fdhsjkLszvhjdiasLSk
• 9 years agoHelpfull: Yes(1) No(27)
• Since there is a condition that each question should get at least 2 marks so first we are giving 2 marks to each of 8 questions.After giving 2 marks to each of 8 questions we have remaining (40-(8*2))=24 marks.Again this 24 marks we have to distribute to 8 questions.This can be done by the rule n+r-1Cr-1.Here n is 24 and r is 8.So the ans is
  24+8-1C8-1=31C7
• 8 years agoHelpfull: Yes(0) No(0)