There are 16 teams divided in 4 groups. Every team from each group will play with each other once. The top 2 teams will go to the next round and so on the top two teams will play the final match. Minimum how many matches will be played in that tournament?

• In each group No of games played =4C2
  since there are initially 4 groups ,4C2*4=24
  next top 2 teams from the 4 groups move to 2nd round.So no of teams become 8.
  These 8 teams again divided into 2 groups
  No of games =4C2*2=12
  In 3rd round 4 teams,so 4C2*1=6
  4th round Final game =1
  therefore total matches=24+12+6+1=43
• 8 years agoHelpfull: Yes(15) No(2)
• 16 team divided in to 4 groups of 4 team each
  
  let first group team contain A,B,C,D team
  they can play with them self in 6 diff ways (4c2 ways each)
  2nd group=6 ways
  3rd group=6 ways
  4th group=6 ways
  
  from this top 2 team selected total 8 team again they form two group of 4 team in each group
  they can again arrange in 6 ways fir 1st and 2nd 6 ways
  
  from this two group again top two selected total 4 team again 6 ways they can play
  from this two team selected and this two team play final match 1
  6+6+6+6+6+6+6+1=43
  ways
• 8 years agoHelpfull: Yes(4) No(0)
• 31
  by simple maths
• 8 years agoHelpfull: Yes(1) No(4)
• 1 group contains 4 teams and in 4 teams to select 1 winner from them minimum 3 matches required
  so for 4 groups number of matches 4*3=12
  further, from 4 winners from each group minimum 3 matches required to select 1 winner
  so answer is 12+3=15
• 8 years agoHelpfull: Yes(0) No(8)
• 3*2*1=6
  6+1=7
• 8 years agoHelpfull: Yes(0) No(2)
• 31 simple calculation
  
• 8 years agoHelpfull: Yes(0) No(5)
• 43
  24+12+6+1
• 8 years agoHelpfull: Yes(0) No(0)