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Logical Reasoning
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There are 16 teams divided in 4 groups. Every team from each group will play with each other once. The top 2 teams will go to the next round and so on the top two teams will play the final match. Minimum how many matches will be played in that tournament?
Read Solution (Total 7)
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- In each group No of games played =4C2
since there are initially 4 groups ,4C2*4=24
next top 2 teams from the 4 groups move to 2nd round.So no of teams become 8.
These 8 teams again divided into 2 groups
No of games =4C2*2=12
In 3rd round 4 teams,so 4C2*1=6
4th round Final game =1
therefore total matches=24+12+6+1=43 - 9 years agoHelpfull: Yes(15) No(2)
- 16 team divided in to 4 groups of 4 team each
let first group team contain A,B,C,D team
they can play with them self in 6 diff ways (4c2 ways each)
2nd group=6 ways
3rd group=6 ways
4th group=6 ways
from this top 2 team selected total 8 team again they form two group of 4 team in each group
they can again arrange in 6 ways fir 1st and 2nd 6 ways
from this two group again top two selected total 4 team again 6 ways they can play
from this two team selected and this two team play final match 1
6+6+6+6+6+6+6+1=43
ways - 9 years agoHelpfull: Yes(4) No(0)
- 31
by simple maths - 9 years agoHelpfull: Yes(1) No(4)
- 1 group contains 4 teams and in 4 teams to select 1 winner from them minimum 3 matches required
so for 4 groups number of matches 4*3=12
further, from 4 winners from each group minimum 3 matches required to select 1 winner
so answer is 12+3=15 - 9 years agoHelpfull: Yes(0) No(8)
- 3*2*1=6
6+1=7 - 9 years agoHelpfull: Yes(0) No(2)
- 31 simple calculation
- 9 years agoHelpfull: Yes(0) No(5)
- 43
24+12+6+1 - 9 years agoHelpfull: Yes(0) No(0)
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