A circle with radius 6cm and other circle with radius 8cm and their centers are separated by 10cm then what is the chord length?

• 2*r1*r2/d = 2*6*8/10 = (9.6 answer)
• 8 years agoHelpfull: Yes(28) No(2)
• draw two circles asper the given data(form a triangle with sides 10,8,6)
  s=(10+8+6)/2=12
  area=√{12(12-10)(12-8)(12-6)}=24
  Let the height of the triangle(which is half of the chord)=h
  1/2 *10*h=24
  =>h=4.8
  hence length of the chord=2*4.8=9.6
  
  
• 8 years agoHelpfull: Yes(16) No(1)
• 9.6
  x*x+y*y=8*8
  (10-x)(10-x)+y*y=6*6
  x=6.4 put this in first eques u will find the value of y which is half of the length of chord.
• 8 years agoHelpfull: Yes(3) No(2)
• chord length = 2√r2 - d2
  r is here 8
  d is 6
  there for chord length = 11.2
• 8 years agoHelpfull: Yes(0) No(4)
• take area of rhombus formula (D1*D2)/2 = L*B => (10*x)/2 =(8*6) => 9.6 cm
• 8 years agoHelpfull: Yes(0) No(0)
• take triangle as a=6cm, b=8cm, c=10cm
  area=sqart(s(s-a)(s-b)(s-c))
  where s=(a+b+c+)/2=12
  area=sqart(12(12-6)(12-8)(12-10))=24
  
  
  
  
  area=0.5*b*h=24
  
  
  >:h=4.8
  length of chord=2h=9.6
• 8 years agoHelpfull: Yes(0) No(0)