A mixture of 125 gallons of wine and water contains 20% of water. How much water must be added to the mixture in order to increase the percentage of water to 25% of the new mixture?
a) 10 gallons b)8.5gallons c) 8gallons d)8.33gallons

• In 125 gallons of the solution there are 0.2∗125=25 gallons of water. We want to add w gallons of water to 125 gallons of solution so that 25+w gallons of water to be 25% of new solution: 25+w=0.25(125+w) --> w=253≈8.33.
  
  Answer: E.
  
  Hope it helps.
  
• 9 years agoHelpfull: Yes(21) No(1)
• amount of water in mixture= 125*(20/100)=25 gallons
  amount of wine in mixture= 125-25=100 gallons
  amount of water in final mixture = 25% of the new mixture
  so , amount of wine in final mixture = 75% of the new mixture
  let , new mixture= x
  so amount of wine in final mixture= (75/100 )*x..................(1)
  also wine amount is constant because only extra water is added
  so , wine amount = 100
  from equation (1)
  ( 75/100)*x =100
  x=133.33
  amount of water = 133.33-125=8.33 gallons ans.....
• 9 years agoHelpfull: Yes(17) No(0)
• Ans. D)
  Direct formula is= 125*(25-20)/(100-25)
  =8.33
• 9 years agoHelpfull: Yes(6) No(0)
• ans is 8.33 not an elitmus qstion .20/100*125=25 (Water) so 100l wine. now 25+x=(125+x)*25/100 solving this x =8.33
• 9 years agoHelpfull: Yes(1) No(0)
• 125 gallons 20%water
  25gallons water 100gallons wine
  25+X 25
  ----------- = -----
  125+X 100
  x=8.33
• 9 years agoHelpfull: Yes(0) No(0)
• 125 gallons contain 80% wine 20% water means 100gallon wine and 25 gallon water then in mixture X 75% wine and 25% water means new mixture X - >75% of X=100 because in new mixture wine is fixed from old mixture soooo X=133.33 and water=33.33-25=8.333
• 9 years agoHelpfull: Yes(0) No(0)
• as there is 20%water means wine would be 100 litre ..now when we want to increase the percentage of water to 25%
  means 100l of wine must be 75 % of the mixture..
  so, 100l = 75%
  then 100% = 133.33l
  since 25l water is already there ...more water added must be 133.33-100-25= 8.33l
• 9 years agoHelpfull: Yes(0) No(0)
• as there is 20%water means wine would be 100 litre ..now when we want to increase the percentage of water to 25%
  means 100l of wine must be 75 % of the mixture..
  so, 100l = 75%
  then 100% = 133.33l
  since 25l water is already there ...more water added must be 133.33-100-25= 8.33l
• 9 years agoHelpfull: Yes(0) No(0)
• as there is 20%water means wine would be 100 litre ..now when we want to increase the percentage of water to 25%
  means 100l of wine must be 75 % of the mixture..
  so, 100l = 75%
  then 100% = 133.33l
  since 25l water is already there ...more water added must be 133.33-100-25= 8.33l
• 9 years agoHelpfull: Yes(0) No(0)
• as there is 20%water means wine would be 100 litre ..now when we want to increase the percentage of water to 25%
  means 100l of wine must be 75 % of the mixture..
  so, 100l = 75%
  then 100% = 133.33l
  since 25l water is already there ...more water added must be 133.33-100-25= 8.33l
• 9 years agoHelpfull: Yes(0) No(0)
• as there is 20%water means wine would be 100 litre ..now when we want to increase the percentage of water to 25%
  means 100l of wine must be 75 % of the mixture..
  so, 100l = 75%
  then 100% = 133.33l
  since 25l water is already there ...more water added must be 133.33-100-25= 8.33l
• 9 years agoHelpfull: Yes(0) No(0)
• ans d
  let x be added
  ((125*20/100)+x)/(125+x)=25/100
  x=8.33
  
• 9 years agoHelpfull: Yes(0) No(0)
• its not question of elitmus
• 9 years agoHelpfull: Yes(0) No(0)
• water in mixture =>20% of 125=25L
  let x L water was added then
  A/q
  25+x=1*(125+x)/4
  x=25/3=>8.33L(ans)
• 7 years agoHelpfull: Yes(0) No(0)