2 identical circles intersect so that their centres and the points at which they interesect form a square of side 1cm . the area in sq. cm of the portion that is common to 2 circles is:
a) sqrt(5)
b) 4
c) sqt(2)-1
d) (pi/2)-1

• answer is (pi/2)-1.
  find the area of sector i.e. (90/360)*pi*(1^2)=pi/4
  area of triangle-(1/2)*1*1=i/2
  area common to both = 2(pi/4 - 1/2) = pi/2 -1
• 8 years agoHelpfull: Yes(13) No(4)
• consider a two circles touching each other and then draw a square inside so that,
  
  Area common to both = 2(π4−12)=π2−1
  
  
• 8 years agoHelpfull: Yes(0) No(3)
• d
  (pi/2)-1
• 8 years agoHelpfull: Yes(0) No(0)
• Ans:a.
  Explanation:by using the formula ,curved surface area of a cone i.e.,pi*r*l, we have to solve this question.
  calculation of "r":diagonal of a square d=sqrt(2)*side;--------------->sqrt(2)*1=sqrt(2).
  --->d=sqrt(2).
  we know that d=2r;
  --->r=d/2;
  ---->r=sqrt(2)/2;
  ---->r=1/sqrt(2);
  given side=slant height(l)=1cm;
  then;
  curved surface area of cone=pi*(1/sqrt(2))*1;
  ------>pi/sqrt(2)=3.14/1.414=2.22;
  so,sqrt(5)=2.22;
  hence answer is :(a)
• 8 years agoHelpfull: Yes(0) No(1)
• d is the right ans
• 8 years agoHelpfull: Yes(0) No(0)