(2020202)^4 find the sum of 5 digits from right side..
option are not remember

• last 5 digit in (2020202)^4
  can be obtained by last 5 digit in (--20202)^4
  (20202)^4
  2^4*(10101)^4
  16*[(10101)^2]^2
  consider only last 5 digit
  16*( 30201)^2
  16*( 00401)
  06416
  
  sum of last 5 digit in (2020202)^4 = 0+6+4+1+6 = 17
  So ans is 17
• 8 years agoHelpfull: Yes(29) No(5)
• take 3 digit it will give more than last 5 digit
  (202)^4=2^4*(101)^4=16*(10201)^2=16*(104060401)
  we can take only last 4 digit.it will enough for last 5 digit
  so, 16*0401=06416
  sum of last 5 digit=0+6+4+1+6=17
• 8 years agoHelpfull: Yes(2) No(0)