How many number of 3's would be used to type numbers from 1 to 700

• 240 is the right answer.
  1-99--20 (3,13,23,30,31,32,33,34,35,36,37,38,39,43,53,63,73,83,93)
  likewise
  100-199--20
  200-299--20
  300-399--120 (300-399 there is extra 100 3's)
  400--499--20
  500--599--20
  600-700--20
  20+20+20+120+20+20+20=240
  
• 8 years agoHelpfull: Yes(50) No(5)
• 240 use pnc
  take upto 699
  first condition
  set 3 at hundredth place as'
  3 _ _
  so total combinations as 1*10*10=100
  coz 3 is fix and there is only one way to gain it, now we can set up digits from 0-9 for other two places.
  
  now similary if we fix 3 at tenth place as'
  _ 3 _
  than there are total possible combinations are as
  7*1*10=70, coz at hundred place we can count upto 7 and at unit place there are 10 possible ways to set up a digit from 0-9
  
  if we set 3 at unit place
  _ _ 3 than
  possibble ways as 7*10*1=70
  so total possible ways are 100+70+70=240
  ANS- 240
• 8 years agoHelpfull: Yes(11) No(3)
• 240. For every hundred a number repeats 20 times so for 700 it is 140 times and in between 300 to 400 the number 3 will come for 100 times
• 8 years agoHelpfull: Yes(8) No(3)
• From 1 to 99 19 3's are there likewise frm 100 to 199 19 3's 200 to 299 19 3's 300 to 399 Its 119 from 400 to 499 19 3's 500
  To 599 its 19 & finaly frm 600 to 700-19 3's
  In total its 19*6+119-Its 233..dis is the correct ans..there are no 20 3's frm 1 to 100 ..33 ll b counted twice in d same case if its 20..233 is the correct ans chums
• 8 years agoHelpfull: Yes(5) No(1)
• Correct ans is 239 times because if we count from 1-100; 3 comes 20 times so as from 101-200 and 201-300 but form 301-400; 3 comes 119 times and again from 401-700 it will com 60 times so in totality
  =>3*20+119+3*20
  => 239 times.
  between 300 to 400 ;3 will come 120 times and as we are counting from 1-100,101-200,201-300 likewise so we are not including 300 when we start counting from 301 to 400.
  Hope this helps :)
• 8 years agoHelpfull: Yes(3) No(5)
• Check for 3 in unit,tens,hundred place
  For unit place divide in groups
  3-99
  103-293
  303-493
  503-693 total 3 in unit place 70
  Same count in tens,place it comes 70
  Lastly for hundred place 300,301-------399 total 99 3 's
  Add all ans is 70+70+99=239
• 8 years agoHelpfull: Yes(2) No(2)
• 20 *6 =120
  from 301 to 400 =120
  sum 240
  
• 8 years agoHelpfull: Yes(2) No(1)
• answer is 486
  1 digit no which do not contain 3=8
  2 digit no. which donot contain 3=8*9
  3 digit no. which donot contain 3 till 699=5*9*9
  and 700=1
  total=8+71+405+1=486
  no. of 3=700-486=214
• 8 years agoHelpfull: Yes(1) No(5)
• Ans: 220.
  Solution: 1 to 99 = 20,
  100 to 199 = 20,
  200 to 299 = 20,
  But in 300 to 399 = 100,
  400 to 499 = 20,
  500 to 599 = 20,
  600 to 699 = 20.
  add all above numbers we get 220 times 3 will occur from 1 to 700. If may wrong please explain me clearly thanks in advance :)
• 8 years agoHelpfull: Yes(1) No(4)
• For every 100 their are 20+1 (for 33) 3s so for 700 we will have 21*7+100 (for all 300 terms), so the answer should be 247
• 8 years agoHelpfull: Yes(1) No(2)
• We know for 0-99 the no of 3's used is 20. Therefore for 1-99 will also be 20 as 3 is greater than 1. The rule is therefore stands as for 0-199 , it will be 20*2= 40 .Similarly, from 1-699 it is 20*7= 140 and therefore from 1 to 700 the value will be 140. Hence answer is 140.
• 8 years agoHelpfull: Yes(1) No(2)
• 219
  between 1to 100 : 20 number of 3's are required,such that for all 1 to 700 ...required 120 num.of 3's ;
  and for 300 to 399 num of 3's are 99
  so 120+99=219
• 8 years agoHelpfull: Yes(0) No(6)
• 220 is the right answer.
  1-99--20 (3,13,23,30,31,32,33,34,35,36,37,38,39,43,53,63,73,83,93)
  likewise
  100-199--20
  200-299--20
  300-399--100(300-399 there is extra 100 3's)
  400--499--20
  500--599--20
  600-700--20
  20+20+20+100+20+20+20=220
  
• 8 years agoHelpfull: Yes(0) No(5)