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Numerical Ability
Permutation and Combination
Inabhi’s class of 44 students,28 students speak malayalam,26 students speak tamil,9 students speak none of the two languages.How many students speak both tamil& Malayalam
a)54 b)38 c)19 d)10
Read Solution (Total 9)
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- (44-9)=28+26-n(A$B)
35=54-n(A$B)
n(A$B)=19 - 9 years agoHelpfull: Yes(13) No(0)
- 28+26-n(M and T)+9=44
n(M and T)=19
M=malayalam T=Tamil - 9 years agoHelpfull: Yes(6) No(0)
- 44-9=(28-x)+(26-x)+x
35=54-x
x=19 - 9 years agoHelpfull: Yes(5) No(0)
- Here, no of student speaking atleast one language (T union M)=44-9=35
Using addition theorem we can have student speaking both language =19
- 9 years agoHelpfull: Yes(2) No(0)
- N(A) = 28
N(B) = 26
N(A U B) = 44 - 9 = 35
N(A n B) = N(A) + N(B) - N(AUB)
N(A n B) = 28 + 26 - 35 = 19
ANSR is 19 - 6 years agoHelpfull: Yes(2) No(0)
- a,it is m intersection t
- 9 years agoHelpfull: Yes(0) No(3)
- None of them speak is =9
So 44-9=35
Both speak languages is:28+26-35=19
So 19 is answer - 6 years agoHelpfull: Yes(0) No(0)
- 44= 28+26+x+9
44=63+x
Therefore x=19 - 4 years agoHelpfull: Yes(0) No(0)
- c
when ehre - 4 years agoHelpfull: Yes(0) No(0)
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