Consider the set of integers 1000,1001,1002,……………………………………..9998,9999 how many integers in this set donot contain the digit 7? A)5832 b)2888 c)1444 d)6746

• Total number of four digit numbers =9000 (i.e 1000 to 9999 )
  We try to find the number of numbers not having digit 7 in them.
  Now consider the units place it can be selected in 9 ways (i.e 0,1,2,3,4,5,6,8,9)
  Tens place it can be selected in 9 ways (i.e 0,1,2,3,4,5,6,8,9)
  Hundreds place it can be selected in 9 ways (i.e 0,1,2,3,4,5,6,8,9)
  Thousands place can be selected in 8 ways (i.e 1,2,3,4,5,6,8,9) here '0' cannot be taken
  Total number of numbers not having digit 7 in it =9 x 9 x 9 x 8 =5832
• 8 years agoHelpfull: Yes(28) No(1)
• Ans= 8*9*9*9=5832
  
• 8 years agoHelpfull: Yes(9) No(1)
• numbaer of 4 digits number is 9*9*9*9 except 7
  5832 answer is
• 8 years agoHelpfull: Yes(1) No(7)
• 8*9*9*9=5832
• 6 years agoHelpfull: Yes(0) No(0)
• thousand place hundred place ten place unit place
  except 0 and 7 except 7 except 7 except 7
  so 8 ways so 9 ways so 9 so 9
  
  8*9*9*9 = 5832
• 5 years agoHelpfull: Yes(0) No(0)