.Rs19266 is distributed among a b c such that a gets 4/45 of what b and c get together and c gets 7/12 of what a and b gets together. Find c share a)7098 b)6084 c)4056 d)8112

• Let A's share is x and similarly for b & c, y& z
  According to question
  19266=x+y+z
  & z=7/12 of (x+y)
  So x+y = 12/7 of z
  Putting value of x+y in 1st equation
  19266=z+z(12/7)
  On solving z=7098
• 8 years agoHelpfull: Yes(16) No(0)
• a+b+c = 19266
  49(b+c)/45 = 19266
  19(a+b)/12 = 19266
  Hence:
  a + 19266*(45/49) = 19266 = 1572.73
  b = 19266*12/19 - a = 10595.27
  
  Therefore:
  c = 19266*45/49-b = 7098
• 8 years agoHelpfull: Yes(2) No(1)
• a = 4/45(b+c)
  c= 7/12(a+b)
  a+b+c = 19266 -----eq1
  Now,replace value of a+b by using c after multipy by 7/12 both side
  7/12c +c = 19266*7/12
  
  c = 19266*7/19
  ans is 7098
  
  
• 8 years agoHelpfull: Yes(2) No(0)
• a+b+c=19266
  &
  12c=7(b+c)
  12c=7*(19266-c)
  19c=134862
  c=7098
• 8 years agoHelpfull: Yes(2) No(0)
• ans a)7098
• 8 years agoHelpfull: Yes(1) No(0)
• c = (7/12)(a+b)
  a+b=12c/7
  a+b+c=19266
  12c/7 + c = 19266
  on solving we get c= 7098
  thanks.
• 8 years agoHelpfull: Yes(1) No(0)
• Let a+b+c=19266
  a=4/45 of (b+c) ----- (1st equation)
  c=7/12 of (a+b) ----- (2nd equation)
  
  From 2nd Equation,
  c=7/12 of (a+b)
  (a+b)= 12/7 of c ----- (3rd equation)
  
  Sub 3rd Equation in,
  a+b+c=19266
  12/7 c + c = 19266
  12c+7c = 19266 * 7
  19c=134862
  
  c=7098 (Answer)
• 8 years agoHelpfull: Yes(1) No(0)
• a=4/45(b+c) ........1
  c=7/12(a+b)
  
  or, (a+b)=12/7c..........2
  
  Also a+b+c=19266
  From 2, 12/7c+c=19266
  c=19266*7/19=7098
• 8 years agoHelpfull: Yes(0) No(0)