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Numerical Ability
Time and Work
.y can do a work in 2/3 the time it takes x, z can do same work in ¾ time it takes y. when all three are typing the same time what is the fraction of total work does y do a)4/13 b)8/29 c)1/3 d)9/23
Read Solution (Total 15)
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- as per data.. Y=2/3x---- (1) and Z=3/4Y----(2)
and they all type the same time X+Y+Z=1----(3)
and from equations (1) and (2) substitute interms of Y in eq (3)
3/2Y+Y+3/4Y=1
(6Y+4Y+3Y)/4=1
13Y/4 =1
Y=4/13
therefore ans is Y=4/13 - 9 years agoHelpfull: Yes(14) No(7)
- let x can do 60 units of work in 1 minute .
then y can do 40 units and z can do 30 units of work.
let them type for a minute .. total work done will be 120 unit
then y's fraction of work = 40/120 = 1/3
option c is correct - 9 years agoHelpfull: Yes(4) No(12)
- suppose, x can do a work in 60 mins. y will take 40 mins and z will take 30 mins to complete the work. all are typing for suppose 60 mins. z will type 2 work, y will type 1.5 work, x will type 1 work. total 2+1.5+1=4.5. out of 4.5 y had done 1.5 work. that's why 1/3 is the ans.
- 9 years agoHelpfull: Yes(4) No(0)
- Efficiency of x and y in the ratio is x : y :: 3 : 2
Efficiency of x and y in the ratio is y : z :: 4 : 3
this is in the form of x : y : z
3 : 2
4 : 3
So all three efficiencies are in the ratio x : y : z :: 12 : 8 : 6
Now, y = 8/26 => 4/13
- 9 years agoHelpfull: Yes(4) No(0)
- Errors @ MOUSOM CHATTERJEE
correction
let x can do 60 units of work in 1 minute .
then y can do 40 units and z can do 30 units of work.
let them type for a minute .. total work done will be 130 unit
then y's fraction of work = 40/130 = 4/13
- 9 years agoHelpfull: Yes(3) No(2)
- 4/13
y=t
x=1.5t
z=0.75t
ans =y/(x+y+z) - 9 years agoHelpfull: Yes(2) No(0)
- X : Y= 3:2
Y : Z= 4:3
X :Y:Z= 6:4:3
Y= 4/(6+4+3) => 4/13 - 9 years agoHelpfull: Yes(2) No(0)
- I think the answer is 1/3
people, efficiency and time are inversely proportional
if y take 2/3 time taken by x to complete a task means y is more efficient than x
say x can do the task in 60 min,
then y complete it in 2/3 x 60 = 40 min
and z complete it in 3/4 x 40 =30min
now say they have got 120 unit of work to complete ( any number can be taken better go for LCM of 60,40,30)
then, x can do 120/60 units of work in a minuite = 2
y can do 120/40 units of work in a minuite = 3
z can do 120/30 units of work in a minuite = 4
2,3,4 are nothing but efficiency of x,y,z
now compute the part of work that y does i.e in a minuite both x,,and z complete 9(2+3+4) units of work out of which y does 3 units.
So ratio = 3/9 = 1/3 - 9 years agoHelpfull: Yes(1) No(1)
- opt (c)
y= 2/3 x
z=3/4 y
now,
let x does 12 hrs of work by taking lcm of 3,4
so y =2/3*12=8 hrs
z=3/4*8=6hrs
so now total units in 1 day== 1/12:1/8:1/6 = 2:3:4
so,y=3/(2+3+4)=1/3
- 9 years agoHelpfull: Yes(1) No(0)
- Let X take a hr to do a work
So y takes 2/3 a hr
Z takes 3/4 * 2/3 a = a/2 hr
Working together their 1 day work
2/a + 1/a + 3/2a
=9/2a
Therefore they will complete in 2a/9 days
Y's contribution=3/2a * 2a/9
=1/3 ans
- 9 years agoHelpfull: Yes(1) No(1)
- yes time is inversly proportional to efficiency
let x can do a work in 12 min
then y can do it 12*2/3=8min
and z can do it in=8*3/4=6 min
let total work is to make 24 unit (LCM of 12,8,6)
then x can make 24/12= 2 unit/min
y can make 24/8=3 unit/min
z canmake 24/6=4 unit/min
total 9 unit/min if all combinely work
then y's share is 3 out of 9 unit
mean 3/9=1/3 (ANS) - 8 years agoHelpfull: Yes(1) No(0)
- yup .... a blunder indeed .. was in a hurry :P correction appreciated
- 9 years agoHelpfull: Yes(0) No(0)
- The time taken by the X to complete the work is 3a
The time taken by the Y to complete the work is 2a
The time taken by the Z to complete the work is 3/4(2a)=3a/2.
one day work of X, Y and Z is=9/6a
we know that one day work of Y is 1/2a
ratio of one day work done by Y to work done by X,Y and Z=1/3
- 9 years agoHelpfull: Yes(0) No(1)
- Y=2/3*X and Z=3/4*Y
So, ratio of x:y:z is
3:2
4:3
------
3*4:4*2:3*2
12:8:6
6:4:3
Y 's fraction of work =4/6+4+3 =4/13 - 8 years agoHelpfull: Yes(0) No(1)
- ans will be 1/3
- 8 years agoHelpfull: Yes(0) No(0)
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