TCS
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Numerical Ability
Number System
Find the number of zeroes in the expression 15*32*25*22*40*75898*112*125.
options are
7/12/14/9
Read Solution (Total 8)
-
- a) 7
To find number of zeros in particular no. just find the factors of that no. and count the occurrences of 5 that'll be the no of zeroes..
so here..
in the expression 15*32*25*22*40*75898*112*125.
15=3x5
32=2x2x2x2x2
25=5x5
22=2x11
40=2x40
75898=2x37949 (You will not get any 5 in this no so leave it..)
112=2x2x2x2x7
125=5x5x5
here the occurrence of 5 is=7 so no of zeros is 7 only !
- 9 years agoHelpfull: Yes(19) No(6)
- Ans: (d) 9
- 9 years agoHelpfull: Yes(9) No(2)
- 15*32*25*40*75*98*112*125
15 - one 5
32 - five 2s
25 - two 5s
40 - three 2s and one 5
75 - one 3 and two 5s
98 - one 2 and two 7s
112 - four 2s and one 7
125 - three 5s
In total: thirteen 2s and nine 5s.
soooo 9 is correct - 9 years agoHelpfull: Yes(4) No(1)
- ans: 7
15= 5*3 ( one 5 )
25= 5*5 (two 5 )
similarly 40 has 1, 125 has 3
count of number of 5s= 1+2+1+3=7
- 9 years agoHelpfull: Yes(3) No(2)
- Ans will be 9...when u will multiply u will find there is 7 zeros at end while 2 in b/w...hence total 9
- 9 years agoHelpfull: Yes(1) No(1)
- if question is 15*32*25*40*75*98*112*125
then no. of zero is 9
if question is 15*32*25*22*40*75898*112*125
then no. of zero is 7 - 9 years agoHelpfull: Yes(1) No(0)
- ans:- (a) 7
- 9 years agoHelpfull: Yes(0) No(1)
- Ans is a)7 hints count number of 5
- 9 years agoHelpfull: Yes(0) No(0)
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