Rani and Shakil run a race of 2000 in First. Rain gives Shakil a start of 200 in and beats him by 1 minute
Next Rani gives Shakil a start of 6 min and is beaten by 1000 metres. Find the time in minutes in in which Rani
and Shakil can run the race separatelv

8,10 /10,12 /12,18 /10,18

• First, Shakeel covers a distance of 1800 and Rani covers a distance of 2000. but Shakeel takes 1minuter more. so,
  Speed of Rani = 2000/x
  Speed of Shakeel = 1800/(x+1)
  
  Second, Shakeel covers certain distance in 6 mins and then Rani starts but cover only 1000m. So total time that Shakel runs is (6+x/2) mins.
  therefore,
  Distance covered by Shakeel = Speed x time
  2000= [1800/(x+1)](6+x/2)
  2000(x+1) = 10800 + 900x
  2000x - 900x = 10800- 2000
  x = 8800/ 1100
  x= 8 mins
  Rani took 8 mins
  So option 1) is correct
• 8 years agoHelpfull: Yes(8) No(1)
• I didn't understand clearly how he got (6+x/2) can anyone explain clearly
• 8 years agoHelpfull: Yes(5) No(2)
• let d is the speed of shakil
  
  
  when rain runs 2000 m shakil runs =1800-d*1..eq 1;
  when rain runs 1000 m shakil runs=2000-d*6 ...eq 2;
  eq 1/eq 2;
  
  2000/1000=(1800-d*1)/(2000-d*6);
  d=200 m/min;
  time taken by shakil =2000/200=10 min;
  time taken by rain =8 min
  
  
  
  
  
• 8 years agoHelpfull: Yes(3) No(3)
• 
  Let rani takes x mins, shakil takes x+1,
  speed of rani =2000/x,
  speed of shakil = 1800/(x+1)
  
  rani cover 1000 ---- (x/2)mins
  shakil takes 6 mins more to cover same distance --- 6+(x/2)
  
  distace = speed * time
  2000 = (1800/x+1) * (6+(x/2))
  2000(x+1) =900(12+x)
  11x=88
  x=8 mins
  rani takes 8mins,
  shakil takes = 6+(8/2) =10 mins
• 8 years agoHelpfull: Yes(3) No(3)
• let Rani complete 2000 m in t min then speed of rani is 2000/t
  similarly shakil complete 1800 m in t+1 min then speed of shakil is 1800/t+1
  
  next ,rani gives start of 6min then beaten by 1000 m then
  2000/(1800/t+1) - 1000/(2000/t) = 6
  t = 8 min means time taken by rani to complete the race is 8 min
  then speed of shakil is 1800/9 =200
  then time is equal to 2000/200 = 10 min
• 8 years agoHelpfull: Yes(1) No(0)
• please explain this Q ...!!!!
• 8 years agoHelpfull: Yes(0) No(0)