(1-1/3^2)(1-1/4^2).....(1-1/2015^2)=x/2015 then x=?

• hey a/c given: (1-1/3^2)(1-1/4^2).....(1-1/2015^2)
  use a^2-b^2 = (a-b)*(a+b);
  applying above we get series as;
  (1+1/3)*(1-1/3)*(1+1/4)*(1-1/4).....................(1+1/2015)*(1-1/2015)
  = 4/3*2/3*5/4*3/4*6/5*4/5*7/6*..............2016/2015*2014/2015
  = 2/3 * 2016/2015
  => 1344/2015 = x/2055;
  hence x = 1344. i hope it is easy to understand
• 9 years agoHelpfull: Yes(23) No(0)
• here it is somehow tricky question..
  answer for this question is = 1344/2015 ;
  hence x 1344
• 9 years agoHelpfull: Yes(3) No(0)
• I solved this one...i think answer would 4032/2015....
  
  above equation can be written as
  (2.4/3^2)(3.5/4^2)(4.6/5^2)...........(2014.2016/2015^2)
  => (2.2016)/2015
  =>4032/2015.
  I dont remember the options bcoz when i was about to solve this one, it was already time out.
  
• 9 years agoHelpfull: Yes(2) No(5)
• x=2014??was dere any option of such sort..
• 9 years agoHelpfull: Yes(0) No(1)
• @Abhishek nkumar can u plz explain in detail..!
• 9 years agoHelpfull: Yes(0) No(0)
• can sum1 tell d options???
• 9 years agoHelpfull: Yes(0) No(0)
• I solved this one...i think answer would 4032/2015....
  
  above equation can be written as
  (2.4/3^2)(3.5/4^2)(4.6/5^2)...........(2014.2016/2015^2)
• 9 years agoHelpfull: Yes(0) No(1)