the question was given with a diagram that i am trying to explain. it goes like..
innermost hexagon has each side=3mm. There are 20 consecutive concentric hexagons. Distance between 2 consecutive hexagon is 5mm. Find the total length of the web (perimeter of all 2 hexagons) including 3 diagonals

• ans is 6.243 inner hexagon side =3 then second 8 third 13 .......... so series wou;d be like 3,8,13............98 sum =20/2(2*3 +19*5)=6060 now diadonal would be twicw the side lenhth .......ie for side 3mm diagonal is 6mm so last diagonal would be of lnght=(19*5+3)*2*3=196*3=588 so total =6060+588=6648mm
  
• 9 years agoHelpfull: Yes(7) No(1)
• a spider web consists of 3 concurrent lines forming radial support for 20 concentric regular hexagon .the hexagon vertices are 5mm from their immidiate neighbour. if the innermost hexagon has a side length 3mm how many meters is the length of the entire web including the 3 diagonals ?
• 9 years agoHelpfull: Yes(2) No(0)
• There are 20 concentric hexagon starting length from 3 and next is 5 more than previous i.e;
  3,8,13,18.........98 total 20terms
  
  Sn=20/2(3+98)=1010
  
  becz hehagon has 6 sides so total lenght=1010*6=6060
  
  And now calculate three concurrent line which are radii of hexagon
  
  we know that radii =2*length of hexagon
  
  but the concurrent line is lenth b/w the vertices of hexagon
  
  so length=2*side*2
  
  = 2*98*2=392
  
  for three lines=392*2=784
  
  
  now total length =6060+784=6844 mm (ANS)
• 8 years agoHelpfull: Yes(1) No(0)
• *perimeter of all 20 hexagons
• 9 years agoHelpfull: Yes(0) No(0)
• i think it would be 1764 mm
• 9 years agoHelpfull: Yes(0) No(2)
• ans optn:7.5,6.2,6.04 wat is ans
• 9 years agoHelpfull: Yes(0) No(0)
• a spider web consists of 3 concurrent lines forming radial support for 20 concentric regular hexagon .the hexagon vertices are 5mm from their immidiate neighbour. if the innermost hexagon has a side length 3mm how many meters is the length of the entire web including the 3 diagonals ?
• 9 years agoHelpfull: Yes(0) No(0)