a peacock is sitting on a 19 m long pole, a snake is approaching the hole which is at bottom of the pole, the snake is 27 m away from the hole, if their speeds are same, find the distance from the hole at which the peacock pounces over the snake.
a. 3.4 m b. 6.8 m c. 5.9 m d. 7.3 m

• They both have same speed hence if snake moves 'x' then peacock also moves 'x' but diagonally down from the pole...
  hence path of peacock , ground, and the pole make a triangle...... with diagonal (Hypotenuse) = x
  snake moves 'x' hence distance left =( 27 - x ) which is the base of triangle
  and height of the pole is the height of triangle =19.
  now, apply pythagoras' theorem----- x^2= (27-x)^2 + 19^2
  solve the equation ..... x= 20.18 m
  And the distance from the hole at which the peacock pounces over the snake = 27 - 20.18 = 6.8
  Answer= 6.8
  
• 9 years agoHelpfull: Yes(15) No(2)
• pole is 19 m long (perpendicular)
  and
  snake distance is 27 m (base)
  (19m)
  |
  |
  |
  |
  |..............................(27m)
  
  if peacock tries to catch snake then it would make triangle (i.e. hypotenuse)
  let hypotenuse be of " X m "
  but snake already traveled some distance thus it travels (27 - X) m distance
  
  Now To find X value we can apply Pythagoras theorem i.e
  
  hypotenuse^2 = base^2 + perpendicular^2
  
  Thus,
  
  X^2 = (27 - X)^2 + 19^2
  
  By solving it We will find
  X = 20.18
  
  Now To find the distance from the hole at which the peacock pounces over the snake
  We have to put the X value to the (27-X) m i.e. Hypotenuse
  
  Therefore, 6.82 will be the answer
• 8 years agoHelpfull: Yes(9) No(0)
• Dear Saikumar,
  x is the distance traveled by both snake and peacock hence - x meters is correct.
• 9 years agoHelpfull: Yes(1) No(2)
• pk___
  ||
  || (x)
  ||(19)
  ||...................... $
• 9 years agoHelpfull: Yes(1) No(4)
• Please give d answers
• 9 years agoHelpfull: Yes(0) No(2)
• Here Divyanshu "x" is in m/s not mts....
• 9 years agoHelpfull: Yes(0) No(2)
• plz explain clearly
• 7 years agoHelpfull: Yes(0) No(0)