if m+ (m-3)-1 = 6 then determine the value of (m-3)2 + (m-3)-2
a. 3 b -1 c. 1 d. 0

• given (m) + (m-3)^-1 = 6.
  now split 6 as 3+3 and then send one of the 3 to the other side of equal to then the equation becomes as
  
  (m-3) + (m-3)^-1 = 3 now take m-3=x
  x+(1/x)=3.
  [ x+(1/x)]^2 = 9
  (x)^2 + (1/x)^2 + 2 = 9 now by resubstituting x=m-3
  
  (m-3)^2 + (1/m-3)^2 = 7
• 8 years agoHelpfull: Yes(19) No(9)
• m=5 substitute in the given equations i.e.,5+(5-3)-1=6,(5-3)2+(5-3)-2=4 , so ans=4
• 8 years agoHelpfull: Yes(15) No(15)
• 2m-6-2m+6=0
• 8 years agoHelpfull: Yes(10) No(8)
• Given 2m-4=6
  m-2=3
  m-3=2(add -1 on both sides)
  substitute in (m-3)2+(m-3)-2
  =(2)2+2-2
  =4
  so ans=4
• 8 years agoHelpfull: Yes(6) No(2)
• D.0
  2m-6-2m+6=0
  
• 8 years agoHelpfull: Yes(4) No(5)
• By solving the first eq we get m=1
  substitute m value in second eqn
  i.e., (1-3)^2+(1-3)-2=0
• 8 years agoHelpfull: Yes(3) No(0)
• Answer is purely based on whether that is (m-3)*(-2) or just (m-3)-2
• 8 years agoHelpfull: Yes(2) No(0)
• m+(m-3)-1=6
  2m-4=6
  2m=10
  m=5 ,so (m-3)2+(m-3)-2 = (5-3)2+(5-3)-2 =0
  
• 8 years agoHelpfull: Yes(2) No(2)
• m=6
  6-6=0
• 8 years agoHelpfull: Yes(1) No(0)
• m+(m-3)-1=6
  2m-4=6
  2m=10
  m=5
  now substitute value in equation 2
  (5-3)2+(5-3)-2
  2(2)+0
  4
  so ans is 4
• 8 years agoHelpfull: Yes(1) No(3)
• m(m-3)-1=6
  m+m-4=6
  m=5
  So,
  put value in given ,
  (m-3)2+(m-3)-2=4
• 8 years agoHelpfull: Yes(1) No(4)
• m+(m-3)-1=6
  2m-3-1=6
  2m-4=6
  2m=10
  m=5
  put this m=5 in second equation, we get
  (5-3)2+(5-3)-2
  2(2)+(2)-2
  4+0= 4
  ans is 4.
• 7 years agoHelpfull: Yes(1) No(0)
• the options are wrong.... the ans is 4
  solving 1st eqn, m=5, putting in 2nd function ans is 4
• 7 years agoHelpfull: Yes(1) No(0)
• answer is 4
• 8 years agoHelpfull: Yes(0) No(1)
• on solving eqn we get m=5
  then put value of m in another eqn
  we get m=4
  ans=4
• 8 years agoHelpfull: Yes(0) No(3)
• By substituting m=(5-3)2+(5-3)-2=5-6+5-3=10-9ansr is 1 option c , calculation is done based on bodmas rule
• 8 years agoHelpfull: Yes(0) No(3)