Elitmus
Exam
Logical Reasoning
Cryptography
is (a*b*c) is even?
1. a-b=b-c
2. a-c=16
Guys plz solve this. I had given today. plz tell correct ans.
Read Solution (Total 30)
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- Neither stat1 nor Stat2 gives the solution alone.And Both statements also can't
- 9 years agoHelpfull: Yes(30) No(1)
- both 1 & 2 are not sufficient to answer the question.
case 1 : b is arithmetic mean of a & c ; if a = 15 , c = 7 , then b = 11 , hence abc is odd ; but a = 8 , c = 4 gives b = 6 and abc is even, hence 1 alone cannot determine
case 2 : a-c = 16, its obvious nothing can be determined about abc from this statement alone.
Now, combining both statements , say, a = 25 , b = 17 , c = 9 , (a - c = 16 and a-b = b-c) then abc is odd , but, if a = 24 , b = 16 and c = 8 (a - c = 16 and a-b = b-c) gives abc even.
hence, nothing can be said about the product abc from the two statements
- 9 years agoHelpfull: Yes(17) No(0)
- a=24
b=16
c=8
then,
a-b=b-c
is
26-16=16-8
8=8
and
a-c=16
is
24-8=16
and then (a*b*c) is 3072 which is a even no. - 9 years agoHelpfull: Yes(7) No(14)
- Crypto Was:
X D L
H A E
-----------
D E P H
3 P K P
__ A D __
------------
P __ __ K D H I AM UNABLE TO FLASH BACK THE EXACT 2 CHARACTERS SO I LEFT BLANK.BUT I AM GIVING THE EXACT SOLUTION OF THE ABOVE CRYPTO:
5 4 7
3 6 9
________
4 9 2 3
3 2 8 2
1 6 4 1
___________
2 0 1 8 4 3 SO SIMPLY YOU HAVE TO PUT THE VALUE OF 1 AND 0.I CAN'T CALL BACK THE VALUE OF 0
AND 1.
Q.1 WAS:D*H*E=4*3*9=108
Q.2 WAS:P*D*K=2*4*8= 64
Q.3 WAS:X*P*__=5*2*1= 10 THE VALUE OF 1 CAN'T CALL FRIENDS.
- 9 years agoHelpfull: Yes(5) No(6)
- both alone can give the ans
- 9 years agoHelpfull: Yes(3) No(6)
- it a=3 b=2 c=1 then (a*b*c)=6 is even no and a,b,c are distinct values as per stmt 1 a-b=1 & b-c=1 so a-b=b-c which gives the solution alone.
- 9 years agoHelpfull: Yes(2) No(4)
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- 9 years agoHelpfull: Yes(2) No(1)
- form statement 2 the diff of a and c is even(i.e., 16)
as odd-odd=even and even-even=odd so both a and b are either two even numbers of odd numbers.
From statement 1 it is clear that a b and c are three consecutive numbers.
for example a=44,b=45,c=46 so a-b=44-45=-1, b-c=45-46=-1
-1=-1
In three consecutive numbers if two terminal numbers(i.e., a and c in abc) are odd then the middle one is always even and if the two terminal numbers are even then the middle number is always odd
Case 1.
let us assume that if both a and b (statement 2) are even then b is odd(by statement 1)
then a*c=even*even=even
(a*c)*b=even*odd=even
Case 2.
let us assume that if both a and b (statement 2) are odd then b is even(by statement 1)
then a*c=odd*odd=odd
(a*c)*b=odd*even=even
In Both the cases the result is even so YES a*b*c is even.
And for calculating the answer both statements are required.
- 8 years agoHelpfull: Yes(2) No(3)
- in elitmus i got
66% in verbal
87% in problem sloving
30% in quant ????is there any chance to get the call????? - 9 years agoHelpfull: Yes(1) No(14)
- Solving statement 1 & 2 : a+c=2b and a-c=16, we get 2a-2b=16 ie. a-b=8. Now solving a-b=8 and a-c=16, we get b-c=8. Now we have 3 eqns a-b=8, b-c=8, a-c=16. Putting values a=20, b=12, c=4, we get abc as even but putting values a=16, b=8, c=0 we get abc=0 which is neither even nor odd. So neither statement 1 nor 2 gives the solution.
- 9 years agoHelpfull: Yes(1) No(0)
- stmt1: a+c=2b so 2b is a even number and it's getting by addition of a+c
now it is possible when odd+odd=even and even+even=even so from the statement 1 it can't say that a,c is actualy even or odd and b is even or odd
stm2:a-c=16 again 16 is even number and its getting by the rule odd-odd=even or even - even=even so we can say that a,c is even or odd so statement 2 is not sufficient
Both stm1&stmt2: from both the statement we can't say a,b,c is even or odd so
answer is both statement 1 and statement 2 is not sufficient to give the answer need another data - 8 years agoHelpfull: Yes(1) No(0)
- 1 is sufficient since they form AP
2 cannot prove us whether product can be even or not - 8 years agoHelpfull: Yes(1) No(0)
- cases
1. odd * odd * odd = odd
2. odd * odd * even = even
3. odd * even * even = even
4. even * even * even = even
so... its only first case that we have to work on... to confirm about the question
NOTE : so here we need to prove ...that case 1st wont exist here.
if case 1 doesn't exist ....yes we can say ..it is even
but if case 1 exist then we can say... some are even some are odd... so no conclusion.
now choose statement 2
put simple odd values a= 17 and c=1
17-1 = 16 true
also put this in 1 eq.
17-b = b -1
this will yield b = 9
so...a=17 , b =9, c = 1
this holds true for both statements
but when we check
17*9*1 = odd
so there exists case 1..
so no conclusion - 8 years agoHelpfull: Yes(1) No(0)
- Even using hit and trail method you will get a=24 b=16 & c= 8
- 8 years agoHelpfull: Yes(1) No(0)
- Both together are sufficient.
- 8 years agoHelpfull: Yes(1) No(0)
- 1. Perimeter of rhombus is equal to perimeter of circle. Longest distance between two points in rhombus is 80. Area of rhombus is 2400 cm^2. Find area of circle.
Options: 10000, 62500, 2500, one more I don't Remember.
Someon Please post this que. I am not able to post. - 9 years agoHelpfull: Yes(0) No(0)
- in elitmus i got
66% in verbal
87% in problem sloving
30% in quant ????is there any chance to get the call?????
- 9 years agoHelpfull: Yes(0) No(9)
- Anybody remember the horse problem in lr di section please post it.. !!
- 9 years agoHelpfull: Yes(0) No(1)
- a=18
b=10
c=2
a*b*c=even no
18-10=8-2
18-2=16 - 9 years agoHelpfull: Yes(0) No(2)
- both are not true
1) Let a=3 b=2 c=9
2- 3 != 3 -9
2)
3-9 != 16
- 8 years agoHelpfull: Yes(0) No(0)
- In cryptarithmetic questions ...are options also given?
- 8 years agoHelpfull: Yes(0) No(0)
- There is a minor mistake in line no 2 of my answer i've posted above.
The correct/updated answer is:
from statement 2 the diff of a and c is even(i.e., 16)
as odd-odd=even
even-even=even
odd-even=odd
even-odd=odd
so it is clear that both a and b are either two even numbers of odd numbers.
From statement 1 it is clear that a b and c are three consecutive numbers.
for example a=44,b=45,c=46 so a-b=44-45=-1, b-c=45-46=-1
-1=-1
In three consecutive numbers if two terminal numbers(i.e., a and c in abc) are odd then the middle one is always even and if the two terminal numbers are even then the middle number is always odd
Case 1.
let us assume that if both a and b (statement 2) are even then b is odd(by statement 1)
then a*c=even*even=even
(a*c)*b=even*odd=even
Case 2.
let us assume that if both a and b (statement 2) are odd then b is even(by statement 1)
then a*c=odd*odd=odd
(a*c)*b=odd*even=even
In Both the cases the result is even so YES a*b*c is even.
And for calculating the answer both statements are required.
- 8 years agoHelpfull: Yes(0) No(4)
- NO,
make it two equation
a+c=-2b and a-c=16 NOW solve it ..
we ll have another equation a=b+8 ,which clears that a is 8 more then the b .
now substitute value of b=1 we will get a=9 abd c=-7
a*b*c=-63 (ODD). - 8 years agoHelpfull: Yes(0) No(0)
- it is consecutive even and odd.
- 8 years agoHelpfull: Yes(0) No(0)
- both statement are not sufficient to hive answer (if a=19,b=11,c=3, )
- 8 years agoHelpfull: Yes(0) No(0)
- a=20
b=12
c=4
1. 20-12=12-4
2. 20-4=16
- 8 years agoHelpfull: Yes(0) No(0)
- a= 18
c=2
a-c= 18-2= 16
a-b = b-c (let b= x)
18-x = x-2
2x= 20
x= 10
So, b= 10
Put all the value in a*b*c = 18*10*2 = 360
So this is even
- 8 years agoHelpfull: Yes(0) No(2)
- Please tell the confirmed, verified and correct Answer, please comment on this fast
- 8 years agoHelpfull: Yes(0) No(0)
- a-b=b-c
a-c=2b
16=2b
b=8
one number is even i.e. b=8
product of a*b*c=even, if any of one number of them is even
i.e. a*8*c=even . - 8 years agoHelpfull: Yes(0) No(2)
- Both 1 & 2 are not sufficient to answer the question.
Let a = 20 b=4 c =12 then both the equation will be satisfied
but
if we take a =19 b= 11 c=3 then also both the equation will be satisfied .
and much more pairs can be made so we cannot give a unique solution . - 2 years agoHelpfull: Yes(0) No(0)
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