Elitmus
Exam
Numerical Ability
Age Problem
if 1/a + 1/b + 1/c = 1/(a+b+c) where a+b+c !=(not equals) 0, abc != 0 , then what is the value of X=(a+b) (b+c) (c+a)+(a+b+c)?
Read Solution (Total 11)
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- x = a+b+c
because, (a+b)(b+c)(c+a) = 0 - 9 years agoHelpfull: Yes(9) No(0)
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- 9 years agoHelpfull: Yes(3) No(0)
- Crypto Was:
X D L
H A E
-----------
D E P H
3 P K P
__ A D __
------------
P __ __ K D H I AM UNABLE TO FLASH BACK THE EXACT 2 CHARACTERS SO I LEFT BLANK.BUT I AM GIVING THE EXACT SOLUTION OF THE ABOVE CRYPTO:
5 4 7
3 6 9
________
4 9 2 3
3 2 8 2
1 6 4 1
___________
2 0 1 8 4 3 SO SIMPLY YOU HAVE TO PUT THE VALUE OF 1 AND 0.I CAN'T CALL BACK THE VALUE OF 0
AND 1.
Q.1 WAS:D*H*E=4*3*9=108
Q.2 WAS:P*D*K=2*4*8= 64
Q.3 WAS:X*P*__=5*2*1= 10 THE VALUE OF 1 CAN'T CALL FRIENDS.
- 9 years agoHelpfull: Yes(3) No(0)
- 0
(ab+bc+ca)/abc=1/(a+b+c)
=> abc=a2b+ab2+ac2+a2c+b2c+bc2+3abc
=> a2b+ab2+ac2+a2c+b2c+bc2+2abc=0
(a+b)(b+c)(c+a)=(ab+ac+b2+bc)(c+a)
=abc+ac2+b2c+bc2+a2c+a2b+b2a+abc
=0 - 9 years agoHelpfull: Yes(2) No(4)
- 1/a + 1/b = 1/(a+b+c) - 1/c
(a+b)/ab = c-a-b-c/ (a+b+c)*c /* cross multiply*/
After cancelling (a+b)
1/ab = -1/[ (a+b+c)*c]
Cross multiply
(a+b+c)*c = -ab
ac + bc + c^2 = -ab
ac + ab + bc + c^2 = 0
a(b+c) + c (b+c) = 0
(b+c) * (a+c) = 0
Hence value is 0 - 8 years agoHelpfull: Yes(2) No(0)
- Either >0 or
- 9 years agoHelpfull: Yes(1) No(0)
- a=-b will be the only case so (a+b)(b+c)(c+a) part will be zero. Hence it totally depends on the value of c. So either >0 or
- 9 years agoHelpfull: Yes(1) No(0)
- in elitmus i got
66% in verbal
87% in problem sloving
30% in quant ????is there any chance to get the call????? - 9 years agoHelpfull: Yes(0) No(12)
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- 9 years agoHelpfull: Yes(0) No(0)
- ans is abc
- 8 years agoHelpfull: Yes(0) No(0)
- put a=1 b=2 c=3
answer is abc - 8 years agoHelpfull: Yes(0) No(2)
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